lets assume the right direction as positive direction of motion and left direction as negative direction of motion
m₁ = 0.200 kg
v₁ = velocity of m₁ before collision= 0.750 m/s
v'₁ = velocity of m₁ after collision= - 0.250 m/s
m₂ = 0.200 kg
v₂ = velocity of m₂ before collision= 0 m/s
v'₂ = velocity of m₂ after collision= ?
using conservation of momentum
m₁ v₁ + m₂ v₂ = m₁ v'₁ + m₂ v'₂
(0.200) (0.750) + (0.400) (0) = (0.200) (- 0.250) + (0.400) v'₂
v'₂ = 0.500 m/s
so the glider of mass m₂ moves right at speed of 0.500 m/s
Answer:
<em>a) 2.15 m</em>
<em>b) 123 m</em>
<em>c) 772.8 m</em>
Explanation:
<u>Circular Motion</u>
One point located at a distance r from the center of rotation travels a distance L given by the arc length :
Where is the angle formed during the rotation.
The wheel described in the question has a radius r=4.1 m and a point on the wheel rotates some angles given in each part:
a)
Calculating L
b)
c)
Answer:
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Explanation:
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