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jekas [21]
3 years ago
12

What is the salt that is produced when calcium hydroxide (Ca(OH)2) reacts with sulfuric acid (H2SO4)? CaSH2Ca H2O CaSO4

Chemistry
2 answers:
maksim [4K]3 years ago
6 0

CaSO4

Calcium Sulfate

Wittaler [7]3 years ago
3 0
H2SO4+CA[OH]2=CASO4+2H2O
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Classical bonding in NaH2PO4
lesantik [10]

NaH_2PO_4, a crystal structure with a short symmetrical hydrogen bond.

<h3>What is Classical bonding?</h3>

Classical models of the chemical bond. By classical, we mean models that do not take into account the quantum behaviour of small particles, notably the electron. These models generally assume that electrons and ions behave as point charges which attract and repel according to the laws of electrostatics.

Sodium dihydrogen phosphate is a derivative composed of glycerol derivatives formed by reacting mono and diglycerides that are derived from edible sources with phosphorus pentoxide followed by neutralization with sodium carbonate.

Bonding in NaH_2PO_4

NaH_2PO_4, a crystal structure with a short symmetrical hydrogen bond. Sodium dihydrogen phosphate (NaH_2PO_4) is monoclinic, space group P2,/c, with a= 6.808 (2), b= 13.491 (3), c=7.331 (2)/~, fl=92.88 (3) ; Z=8.

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7 0
2 years ago
What is the potential energy of the reactants from the following energy diagram?
slavikrds [6]
The potential energy of the reactants is 200J.
From the energy diagram, the energy of the product formed is 350J; this means that, this reaction is an endothermic reaction, because it absorbs energy from its environment.<span />
5 0
3 years ago
Read 2 more answers
What is physical weathering? (1 point)
steposvetlana [31]

Answer:

well physical weathering is the process of a element or acts of water rock or other items that take its toll on items

Explanation:

so i would,WITH CONFIDENCE         C.

5 0
2 years ago
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You decide to clean the bathroom. You notice that the shower is covered in a strange green slime . you try to get rid of this sl
Free_Kalibri [48]
  1. The independent variable (IV) is the lemon juice mixture
  2. The dependent variable (DV) is the appearance of the green slime on the shower
  3. The control variable (CV) are time taken to spray, the amount of spray
  4. The experimental group (EG) is the side of the shower sprayed with lemon juice mixture
  5. The control group (CG) is the side of the shower sprayed with water.

INDEPENDENT VARIABLE

  • Independent variable is the variable of an experiment that is changed by the experimenter in order to bring about a change. It is the variable being tested in the experiment. In this case, the IV is the lemon juice mixture tested on the green slime on the shower.

DEPENDENT VARIABLE:

  • Dependent variable is the variable that is observed or measured in an experiment. It is also called responding variable. The DV in this case is the appearance of the green slime on the shower.

CONTROL VARIABLE:

  • Control variable is the variable that is kept constant throughout the experiment for all groups. The CV is the same for all the groups and they include: time taken to spray, the same amount of spray

CONTROL GROUP

  • Control group is the group that does not receive the independent variable or test in an experiment. In this case, the CG is the side of the shower sprayed with water.

EXPERIMENTAL GROUP:

  • Experimental group is the group of ab experiment that receives the experimental treatment or independent variable. In this case, the EG is the side of the shower sprayed with lemon juice mixture.

Therefore, the IV, DV, CV, EG and CG of this experiment are as follows:

  1. The independent variable (IV) is the lemon juice mixture
  2. The dependent variable (DV) is the appearance of the green slime on the shower
  3. The control variable (CV) are time taken to spray, the amount of spray
  4. The experimental group (EG) is the side of the shower sprayed with lemon juice mixture
  5. The control group (CG) is the side of the shower sprayed with water.

Learn more: brainly.com/question/17498238?referrer=searchResults

7 0
2 years ago
CONCLUSIONS: Suppose a student titrated a sample of monoprotic acid of unknown concentration using a previously standardized sol
Zolol [24]

Concentration of unknown acid is 0.061 M

Given:

Concentration of NaOH = 0.125 M

Volume of NaOH = 24.68 mL

Volume of acid solution = 50.00 mL

To Find:

Concentration of the unknown acid

Solution: Concentration is the abundance of a constituent divided by the total volume of a mixture. The concentration of the solution tells you how much solute has been dissolved in the solvent

Here we will use the formula for concentration:

M1V1 = M2V2

0.125 x 24.68 = 50 x M2

M2 = 0.125 x 24.68 / 50

M2 = 0.061 M

Hence, the concentration of unknown acid is 0.061 M

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3 0
1 year ago
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