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Natasha_Volkova [10]

3 years ago

8

Predict the mass of oxygen required to react with 14 g of nitrogen to make N2O5 if 16 g of oxygen reacts with 14 g of nitrogen t

o make N2O2.

1 answer:

Sunny_sXe [5.5K]3 years ago

4 0

Answer:

idk srry

Explanation:

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Assume a density of water of 1.00 g/mL, and calculate the mass of water in the solution

tiny-mole [99]

Answer:

1g or 10^-3kg

Explanation:

as you know , the density =mass \volume

so you have the mass from the number it self

<h2> $\frac{1g}{1 ml}$ so from this equation, you will get 1 g and you can to SI to be $10^{-3}$ kg</h2>

5 0

3 years ago

6 NaOH + 2 Al ???? 2 Na3AlO3 + 3 H2 How much aluminum is required to produce 17.5 grams of hydrogen? How many moles of NaOH are

ANTONII [103]

Answer:

a) 157.5 grams of aluminum.

b) 1 mol

c) 9 g

Explanation:

The reaction is :

$6 NaOH + 2Al ---> 2 Na_{3}AlO_{3} + 3H_{2}$

As per balanced equation

a) 3 moles of hydrogen will be produced from two moles of aluminium.

The atomic mass of aluminium = 27

therefore

3X2 grams of hydrogen is produced from 2 X 27 grams of Al

1 gram of hydrogen will be produced from $\frac{2X27}{3X2}= 9$ g

therefore 17.5 will be produced from = 9X 17.5 = 157.5 grams of aluminum.

b) as per balanced equation three moles or six gram of hydrogen is produced from 6 moles of NaOH.

Therefore 1 g of hydrogen will be produced from = $\frac{6}{6}$

or 1 gram will be prepared from = 1 mole

c) from balanced equation three moles are produced from two moles of Al (27X2 = 54 g).

thus from 54 grams gives 6 grams of hydrogen

1 grams will give = $\frac{54X1}{6}= 9 g$

7 0

3 years ago

Read 2 more answers

A Lay’s potato chip weighing 4.03g is put into a bomb calorimeter containing 895.5g of water at 25.10°C. If this increases the t

erastovalidia [21]

the answer is 28.38 i think

7 0

3 years ago

ASAP PLS 100 POINTS Which statement best describes the role of oxygen in cellular respiration?

Vinvika [58]

It’s A .. I think I hope this helps !

5 0

2 years ago

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Manganese sulfate forms a pale pink hydrate with the formula MnSO 4 ⋅ n H 2 O ( s ) . If this hydrate is heated to a high enough

Mama L [17]

Answer:

Value of n in MnSO₄.nH₂O is one.

Explanation:

The n represents the number of moles of water attached to the formula unit manganese sulfate. These moles (n) can be determined by taking the ratio of the moles of anhydrous salt and the moles of water. The moles of water can be determined by taking the difference of final and initial mass of the salt. This difference is equal to the mass of the water, mathematically it can be represented as,

Mass of H₂O = initial mass of the salt (g) - final mass of the salt (g)

Mass of H₂O = 16.260 g - 14.527 g

Mass of H₂O = 1.733 g

moles of H₂O = (1.733 g) ÷ (18.015 g/mole)

moles of H₂O = 0.0962

For the moles of anhydrous salt:

moles of MnSO₄ = mass of MnSO₄ ÷ molar mass of MnSO₄

moles of MnSO₄ = 14.5277 ÷ 151.001

moles of MnSO₄= 0.0962

Now for n:

n = moles of water ÷ moles of MnSO₄

n = 0.0962 ÷ 0.0962

n = 1

The above calculations show that one mole of H₂O is attached to the one formula unit of MnSO₄

8 0

3 years ago