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qwelly [4]
3 years ago
5

A rigid container of gas has a pressure of 1.72 atm and temperature of 21 oC. If the temperature increases to 85 oC, what is the

new pressure in atm?
Chemistry
1 answer:
Vinil7 [7]3 years ago
5 0

Answer:

the new pressure is 2.09 atm

Explanation:

you have to use gay lussac's law so the formula is

p1/t1 = p2/t2

and convert C to Kelvin k=C+273.15

1.72atm/294.15 = p2/358.15

solve for p2 by multiplying 358.15 on both sides

p2=2.09 atm

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In an endothermic reaction would energy be considered a reactant or a product?
timurjin [86]

Answer:

In an endothermic reaction, the products have more stored chemical energy than the reactants. In an exothermic reaction, the opposite is true. The products have less stored chemical energy than the reactants. The excess energy in the reactants is released to the surroundings

4 0
2 years ago
What mass of KNO3 would be needed to produce 18.4 liters of oxygen gas, measured at 1.50 x 10^3 kPa and 15 degrees Celsius?
Brut [27]

Answer:-

2328.454 grams

Explanation:-

Volume V = 18.4 litres

Temperature T = 15 C + 273 = 288 K

Pressure P = 1.5 x 10^ 3 KPa

We know universal Gas constant R = 8.314 L KPa K-1 mol-1

Using the relation PV = nRT

Number of moles of oxygen gas n = PV / RT

Plugging in the values

n = (1.5 x 10^3 KPa ) x ( 18.4 litres ) / ( 8.314 L KPa K-1 mol-1 x 288 K)

n = 11.527 mol

Now the balanced chemical equation for this reaction is

2KNO3 --> 2KNO2 + O2

From the equation we can see that

1 mol of O2 is produced from 2 mol of KNO3.

∴ 11.527 mol of O2 is produced from 2 x 11.527 mol of KNO3.

= 23.054 mol of KNO3

Molar mass of KNO3 = 39 x 1 + 14 x 1 + 16 x 3 = 101 grams / mol

Mass of KNO3 = 23.054 mol x 101 gram / mol

= 2328.454 grams

7 0
3 years ago
Calculate the temperature change that occurs when 254 cal of heat are added to 24 g of water
Tomtit [17]
Hey

Calculate the temperature change that occurs when 254 cal of heat are added to 24 g of water
answer:  800
3 0
2 years ago
A 46.2 mL,0.568 M calcium nitrate solution is mixed with 80.5mL of 1.396M calcium nitrate solution.Calculate tge concentration o
Ne4ueva [31]

Answer:

1.09 M

Explanation:

Let's define the equation that will be used to calculate the final concentration of the resultant calcium nitrate solution. In order to calculate it, we need to find the total number of moles of calcium nitrate and divide by the total volume of the resultant solution:

c=\frac{n}{V}

This equation firstly helps us find the number of moles of calcium nitrate. Multiplying molarity by volume will yield the moles. Adding the moles from the first component to the second component will provide us with the total number of moles of calcium nitrate:

n_{Ca(NO_3)_2}=46.2 mL\cdot0.568 M+80.5 mL\cdot1.396 M=138.62 mmol

Now, the total volume of this solution can be found by adding the volume values of each component:

V_total=46.2 mL+80.5 mL=126.7 mL

Finally, dividing the moles found by the total volume will yield the final molarity:

c_{final}=\frac{138.62 mmol}{126.7 mL}= 1.09 M

6 0
3 years ago
Can someone help me with this question ASAP
Mkey [24]
Aye i can’t see the full question dawg, you gotta send a full picture of it
6 0
2 years ago
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