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anastassius [24]
3 years ago
14

The ratio of a to b is 2:3, and the ratio of a to c is 3: 10. What is the ratio of b to c?

Mathematics
2 answers:
Stolb23 [73]3 years ago
4 0

Answer: 3:10

Step-by-step explanation:

From the question, b= 3; c=10

Ratio of b:c will be

the value of b:value of c

=3:10

I hope you understand

allsm [11]3 years ago
4 0

Answer: b:c =  9:20

Step-by-step explanation:

a:b = 2:3

That is

\frac{a}{b} = \frac{2}{3}

This means that

a = \frac{2}{3}b ................................... *

Also

a:c = 3: 10

\frac{a}{c} = \frac{3}{10}

which means that

a = \frac{3}{10}c .................................. **

Equate * and ** since they are both values of a

That is :

\frac{2}{3}b =\frac{3}{10}c

cross multiplying , we have

20b = 9c

Therefore :

\frac{b}{c}=\frac{9}{20}

Therefore :

b:c =  9:20

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Mariulka [41]

Answer:

p=12x-10

Step-by-step explanation:

Perimeter is just adding all of the sides' lengths together, so we can put all of them into one big equation and then combine like terms.

p=x+(2x+5)+(6x-17)+(3x+2)\\p=12x-10

Hope this helps!

7 0
3 years ago
Point R is located at (-9,8) and point T is located at (-9,-7) on a coordinate plane.
poizon [28]

Answer:

15 unit

Step-by-step explanation:

Applying

/RT/ = √[(y₂-y₁)²+(x₂-x₁)²]............. Equation 1

Where /RT/ = distance between point R and Point T

From the question,

Given: y₁ = -9, x₁ = 8, y₂ = -9, x₂ = -7

Substitute these values into equation 1

/RT/ = √[(-9-(-9))²+(-7-8)²]

/RT/ = √[(0)²+(-15)²]

/RT/ = √225

/RT/ = 15 unit

Hence the distance between point R and point T is 15 unit

3 0
3 years ago
I am super confused<br> .....................
Phantasy [73]

Answer:

B is the answer

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find y'' by implicit differentiation. 3x^3 + 4y^3 = 5
pochemuha
We first have to find the first derivative before we can find the second.  First derivative with respect to x is 9x^2+12y^2 \frac{dy}{dx}=0 so 12y^2 \frac{dy}{dx}=-9x^2  and  \frac{dy}{dx}=- \frac{9x^2}{12y^2}=- \frac{3x^2}{4y^2}.  That's the first derivative.  Now for the second it's probably easiest to use the quotient rule, even though it's usually long and drawn out.  That looks like this: \frac{dy}{dx}= \frac{4y^2(-6x)-[-3x^2(8y \frac{dy}{dx})] }{(4y^2)^2}  which simplifies a bit to  \frac{dy}{dx}= \frac{-24xy^2+24x^2y( \frac{dy}{dx}) }{16y^4}.  We will multiply both sides by that denominator to get rid of it which leaves us with  16y^4 \frac{dy}{dx}=-24xy^2+24x^2y \frac{dy}{dx}.  Get both dy/dx terms on the same side, and then factor it out.  \frac{dy}{dx}(16y^4-24x^2y)=-24xy^2.  Divide to isolate the dy/dx: \frac{d^2y}{dx^2}= \frac{-24xy^2}{16y^4-24x^2y}.  There's no simplifying you could do after that that would make any significant difference.
6 0
4 years ago
Help please I'm horrible at math. Please help!!
Nataly_w [17]
Answer = 1/5 and 4
solved by middle term breaking
4 0
3 years ago
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