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Misha Larkins [42]
3 years ago
5

2 DIVIED BY 1/4= 1/6 DIVIED BY 2=

Mathematics
2 answers:
Iteru [2.4K]3 years ago
4 0

2 dive by 1/4= 8

6 dive by 1/3 = 18

2 dive by 1/3 = 6

5 dive by 1/2= 10

1/6 dive by 2= 1/12

1/3 dive by 6= 1/18

3 dive by 1/4= 12

1/2 dive by 5= 1/10

NemiM [27]3 years ago
3 0

Answer:

f .ds///////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////

Step-by-step explanation:

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I need help with this!
AleksAgata [21]

9514 1404 393

Answer:

  64.6

Step-by-step explanation:

One standard deviation is 4.3. Then +2 standard deviations is ...

  (+2)(4.3) = +8.6

This amount added to the mean gives ...

  56 +8.6 = 64.6 . . . . +2σ from the mean

5 0
3 years ago
#10-12!!! look at picture!!! I don't give out points for free!!! T.T
Tom [10]
F(x)=x
Domain: 1 2 3 4 5 6
Range: 1 2 3 4 5 6

F(x)=2x
Domain: 1 2 3 4
Range: 0 2 4 6
3 0
3 years ago
Read 2 more answers
Please help due in 10 min.
sleet_krkn [62]

Answer:

A: equiangular   S: Right

Step-by-step explanation:

5 0
3 years ago
How do you simplify (4/9)²?
Vanyuwa [196]
(4/9)² = 4²/9² = 16/81 
7 0
3 years ago
Write the equation of a parabola whose focus is at (-7, 3) and whose directrix is the line x = -3.
Sav [38]

Check the picture below.

now, let's keep in mind that, the vertex is half-way between the focus point and the directrix, it's a "p" distance from each other.

since this horizontal parabola is opening to the left-hand-side, "p" is negative, notice in the picture, "p" is 2 units, and since it's negative, p = -2.

its vertex is half-way between those two guys, so that puts the vertex at (-5, 3)

\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ 4p(y- k)=(x- h)^2 \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-5\\ k=7\\ p=-2 \end{cases}\implies 4(-2)[x-(-5)]=[y-7]^2 \\\\\\ -8(x+5)=(y-7)^2\implies x+5=\cfrac{(y-7)^2}{-8}\implies \boxed{x=-\cfrac{1}{8}(y-7)^2-5}

7 0
4 years ago
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