Let the event 'has cancer' be C, and the event 'works for Ajax' be A.
P(C) = 0.0019. P(A) = 0.28
The events A and C are independent if P(C|A) = P(C).
P(C|A) = 0.0019 = P(C).
Therefore the answer is YES.
Answer:
a. the number of people at Friday's, Saturday's, and Sunday's performances combined.
Step-by-step explanation:
The reason this information is needed to solve this problem is because we are looking to find the number of people who attended Saturday's performance. Without any information on Saturday's performance, there is no way to solve the problem. We are given the number of people on Friday and Sunday's performance, but are not given a total amount of people on all performances.
Answer:
yes
Step-by-step explanation:
Weight appears to be the independent variable, so will be graphed on the horizontal axis. Cost is the dependent variable, so will be graphed on the vertical axis.
Answer:
12.3%
Step-by-step explanation:
In this case, despite being different events, they are dependent on each other, therefore the final probability would be the multiplication of both probabilities.
So let L be the probability of being late that is equal to 41% and let T be the probability that the train will leave you and is equal to 30%.
That is to say:
L = 41% = 0.41
T = 30% = 0.3
So:
P = L * T
P = 0.41 * 0.3 = 0.123
So it means that the final probability is 12.3%
