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Vlada [557]
3 years ago
9

At a fundraiser, students sold chocolate bars with almonds and chocolate bars with walnuts. The number of chocolate bars with al

monds that were sold one weekend was 3 less than 2 times the number of chocolate bars with walnuts that were sold. The number of chocolate bars with walnuts plus 4 times the number of chocolate bars with almonds was 300. How many of each kind of chocolate bar were sold that weekend?
Mathematics
1 answer:
BabaBlast [244]3 years ago
6 0

Answer:

Total number chocolate bars with almonds sold were approximately 66.34 and total number chocolate bars with walnuts sold were approximately 34.67.

Step-by-step explanation:

Let number chocolate bars with almonds be x

Also let number chocolate bars with walnuts be y

Given:

Number of chocolate bars with almonds that were sold one weekend was 3 less than 2 times the number of chocolate bars with walnuts.

Framing the above sentence in equation form we get;

x=2y -3

Also given:

The number of chocolate bars with walnuts plus 4 times the number of chocolate bars with almonds was 300.

Framing the above sentence in equation form we get;

4x+y=300

Now Substituting the value of x in above equation we get;

4x+y=300\\4(2y-3)+y=300\\8y-12+y=300\\9y=300+12\\9y=312\\\\y=\frac{312}{9} \approx 34.67

Now we will substitute the value of y in equation x=2y -3 we get;

x=2y-3 = 2\times34.67 -3 = 69.34-3\approx66.34

Hence, Total number chocolate bars with almonds sold were approximately 66.34 and total number chocolate bars with walnuts sold were approximately 34.67.

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