The answer is 2,770.3125 or you want me to check for a other answer
Since the histogram is not symmetric, the grades shown in the math class below are not normally distributed.
<h3>When does a histogram represent a normal distribution?</h3>
A histogram represents a normal distribution if it symmetric.
In this problem, we have that:
- 57% of the grades are on the left tail.
- 25% of the grades are on the center.
- 18% are on the right tail.
Since the percentages at the tails are different, the histogram is not symmetric, and the grades shown in the math class below are not normally distributed.
More can be learned about the normal distribution at brainly.com/question/24537145
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Step-by-step explanation:
Ounces of water = 56 - 14 = 42 ounces
Ratio of sugar to water
56 : 42
8 : 6
4 : 3
(-2,5)(9,-6)
slope(m) = (-6-5) / (9 - (-2) = -11/11 = -1
y = mx + b
slope(m) = -1
(-2,5)...x = -2 and y = 5
now we sub and solve for b, the y int
5 = -1(-2) + b
5 = 2 + b
5 - 2 = b
3 = b
so ur equation in slope intercept form is : y = -x + 3
