Question

Find the equation of the line perpendicular to 4x-y=2 and contains the point (5,-2)

Answer 1

Answer:

y = -1/4x - 3/4

Step-by-step explanation:

First, you need to change the equation into slope intercept form. Subtract 4x from both sides to get -y= -4x + 2. Divide all parts by -1 to get y=4x-2. One thing you should know when finding the slope of a perpendicular line is that the slope is the opposite reciprocal. So, the slope is -1/4. This is your current equation: y= -1/4x + b. Plug the coordinate into the equation; it should look like this: -2= -1/4(5) + b. Multiply -1/4 by 5 to get -5/4. This is what you should have now: -2 = -5/4 + b. Add 5/4 to both sides to get -3/4 = b. Go back to your other equation and plug in -3/4 to b. This is your final equation: y = -1/4x - 3/4. Hope this helped!