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Leona [35]
3 years ago
11

Which expression is equivalent to (4^-5 * 4^4) + (2^6/ 2^3)

Mathematics
2 answers:
andrew11 [14]3 years ago
8 0

Answer:

A

Step-by-step explanation:

BaLLatris [955]3 years ago
5 0

Answer:

A

Step-by-step explanation:

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Snowcat [4.5K]

Answer:

-1

Step-by-step explanation:

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Im stuck please help ( use the PEMDAS)
Lorico [155]

Answer:

4+3+4=11 and (4-2)× 4= 8 and (15×2)÷3=10 and (7-1)÷6= 1and 10+(-3)×10-8=?

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3 years ago
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Write the expression in correct forma<br><br>13n² -6n⁴ + 2n -5n³ + 3<br>​
m_a_m_a [10]

Answer:

-6n^4 -5n^3 +13n^2 +2n +3

organize the exponents from higher to lower.

4 0
3 years ago
A 250-gal tank is initially filled with brine (salt-water mixture) containing 100 lb of salt. Brine containing 3 lb of salt per
gulaghasi [49]

Answer:

x(t) = 581.66 lb

Step-by-step explanation:

From the given information:

Consider the salt quantity in the tank at time t be x(t) lb.

∴ the rate of change of salt content in the tank is \dfrac{dx}{dt}= Rate \ of \  \ inflow - rate \ of \  \ outflow

where:

the rate of inflow = salt conc. × flow rate = 3 lb/gallon × 7 gallons

=21 lb/s

rate of outflow = salt conc. in the tank  × flow rate

= x/250 ×  9

= 9x/250  lb/s

∴

\dfrac{dx}{dt} = 21 - \dfrac{9x}{250}

\dfrac{dx}{dt} + \dfrac{9x}{250}= 21

This is a 1st order linear differentiation,

The integrating factor if e^{^{ \int \dfrac{9}{250}\ dt}} = e^{^{ \dfrac{9t}{250} }}

∴

e^{^{ \dfrac{9t }{250}}} \ \ x(t) = \int 21 e^{\dfrac{9t}{250}} \ dt + C

e^{^{ \dfrac{9t }{250}}} \ \ x(t) =  21 \times \dfrac{250}{9}e^{\dfrac{9t}{250}} + C

x(t) = \dfrac{1750}{3}+Ce^{^{\dfrac{-9t}{250}}}     at  t = (0) and x(0) = 100 lb

Hence;

100 = \dfrac{1750}{3}+C

C = \dfrac{1750}{3} -100

C = - \dfrac{1450}{3}

∴x(t) = \dfrac{1750}{3}-\dfrac{1450}{100}e^{^{\dfrac{-9t}{250}}}

after time t = 1 minute i.e 60 s

x(t) = \dfrac{1750}{3}-\dfrac{1450}{100}e^{^{\dfrac{-9 \times 60}{250}}}

x(t) = \dfrac{1750}{3}-\dfrac{1450}{100}e^{^{\dfrac{-540}{250}}}

x(t) = 581.66 lb

5 0
4 years ago
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