Which statement is TRUE about the flight of 2 rockets?
1 answer:
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Answer:
a) The volume of the sphere is approximately 14,137.16694 which is 14,140 cm³ correct to 4 significant figures
b) The volume of water required to fill the tank is approximately 103,670 cm³
Step-by-step explanation:
a) In the question, the radius of the sphere, r = 15 cm
The formula for the volume, 'V', of a sphere is given as follows;
Where;
r = The radius of the the sphere
V = The volume of the sphere
Plugging in the value for the radius, 'r', of the sphere, in the equation for, 'V', we get;
Therefore;
The volume of the sphere to 4 significant figures is V ≈ 14,140 cm³
b) The parameters of the cylindrical tank are;
The height of the cylindrical tank, h = 60 cm
The radius of the cylindrical tank, r = 25 cm
The volume of a cylinder, V = π·r²·h
∴ The volume of the cylindrical tank without water, '', is given as follows;
= π × (25 cm)² × 60 cm ≈ 117809.72451 cm³
The volume of water, , required to fill the tank with the sphere of volume 'V' placed inside is given as follows
= V +
∴ =
- V
From which we get;
≈ 117809.72451 cm³ - 14,140 cm³ = 103,669.72451 cm³ ≈ 103,670 cm³
The volume of water required to fill the tank, ≈ 103,670 cm³.
The value of "a" is 4
<em><u>Solution:</u></em>
<em><u>Given expression is:</u></em>
The above expression involves variables and constants
A variable is a symbol that represents an unknown number
Here the variable is "a"
Constants are fixed numbers like 1, 2 etc
<em><u>From given expression:</u></em>
Move the varibale "2a" from right side to left side of equation
When, 2a is moved from R.H.S to L.H.S, it becomes -2a
Now move the constant -2 from left side to right side of equation
Similarly, when -2 is moved from L.H.S to R.H.S, it becomes +2
Now add the variables on left side of equation
Now add the constants on right side of equation
Cancel the negative sign on both sides of equation
Thus the value of "a" is 4