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Artemon [7]
3 years ago
10

How do you solve for x in this quadratic equation?: 5x^2 – 34x + 24 = 0

Mathematics
1 answer:
wlad13 [49]3 years ago
5 0
Quadratic formula
factoring
graphing 
completing the square
factoring by grouping
Rational Roots Theorem
synthetic division

Take a look at <span>5x^2 – 34x + 24 = 0.  The last term could have been the result of these different possible muliplications:  1*24, 2*12, 3*8, 4*6.  The leading term is 5, whose factors are 5 and 1.  Thus, possible rational roots would be
4/5 (the 4 is a factor of 24 and the 5 is a factor of 5) and 6/1 (the 6 is a factor of 24 and the 1 is a factor of 5).  

Using synth. div. to check whether 6 is actually a root:
     ___________________
6  /    5      -34          24
                  30         -24
    ------ --------------------------
         5       -4             0

since the remainder is 0, we can safely call 6 a "root."  
Note the remaining coefficients, 5 and -4:  

They correspond to the factor 5x - 4.  If we set this difference = to 0, and solve for x, we get  x = 4/5 (which is correct).

The roots of </span><span>5x^2 – 34x + 24 = 0  are  x = 4/5 and x= 6/1.</span>
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Please help, Easy maths.
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Valuate the expression. Give your answer as a fraction in simplest form.<br> 2/5 X 0.22
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2 years ago
Bigger animals tend to carry their young longer before birth. The length of horse pregnancies from conception to birth varies ac
Shtirlitz [24]

Answer:

a) \mu -3\sigma = 336-3*6=318

\mu+-3\sigma = 336+3*6=354

b) For this case we know that within 1 deviation from the mean we have 68% of the data, and on the tails we need to have 100-68 =32% of the data with each tail with 16%. The value 342 is above the mean one deviation so then we need to have accumulated below this value 68% +(100-68)/2 = 68%+16% =84%

And then the % above would be 100-84= 16%

Step-by-step explanation:

Assuming this question : "Bigger animals tend to carry their young longer before birth. The  length of horse pregnancies from conception to birth varies according to a roughly normal distribution with  mean 336 days and standard deviation 6 days. Use the 68-95-99.7 rule to answer the following questions. "

(a) Almost all (99.7%) horse pregnancies fall in what range of lengths?

First we need to remember the concept of empirical rule.

From this case we assume that X\sim N(\mu = 336. \sigma =6) where X represent the random variable "length of horse pregnancies from conception to birth"

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

From the empirical rule we know that we have 99.7% of the data within 3 deviations from the mean so then we can find the limits for this case with this:

\mu -3\sigma = 336-3*6=318

\mu+-3\sigma = 336+3*6=354

(b) What percent of horse pregnancies are longer than  342 days?

For this case we know that within 1 deviation from the mean we have 68% of the data, and on the tails we need to have 100-68 =32% of the data with each tail with 16%. The value 342 is above the mean one deviation so then we need to have accumulated below this value 68% +(100-68)/2 = 68%+16% =84%

And then the % above would be 100-84= 16%

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The answer is #K12. hope this helps

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