Answer/Step-by-step explanation:
✔️Find EC using Cosine Rule:
EC² = DC² + DE² - 2*DC*DE*cos(D)
EC² = 27² + 14² - 2*27*14*cos(32)
EC² = 925 - 756*cos(32)
EC² = 283.875639
EC = √283.875639
EC = 16.85 cm
✔️Find the area of ∆DCE:
Area = ½*14*27*sin(32)
Area of ∆DCE = 100.15 cm²
✔️Since ∆DCE and ∆ABE are congruent, therefore,
Area of ∆ABE = 100.15 cm²
✔️Find the area of the sector:
Area of sector = 105/360*π*16.85²
Area = 260.16 cm² (nearest tenth)
✔️Therefore,
Area of the logo = 100.15 + 100.15 + 260.16 = 460.46 ≈ 460 cm² (to 2 S.F)
Ojsjsijdjsndjfjfiowjsbdidhejsnfj
Answer:
A
Step-by-step explanation:
3x9+ 27 + 8= 35
Answer: If 7+5i is a zero of a polynomial function of degree 5 with coefficients, then so is <u>its conjugate 7-i5</u>.
Step-by-step explanation:
- We know that when a complex number
is a root of a polynomial with degree 'n' , then the conjugate of the complex number (
) is also a root of the same polynomial.
Given: 7+5i is a zero of a polynomial function of degree 5 with coefficients
Here, 7+5i is a complex number.
So, it conjugate (
) is also a zero of a polynomial function.
Hence, if 7+5i is a zero of a polynomial function of degree 5 with coefficients, then so is <u>its conjugate 7-i5</u>.
