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kifflom [539]
3 years ago
13

A cheesecheese can be classified as either raw dash milkraw-milk or pasteurizedpasteurized. Suppose that 9797​% of cheesescheese

s are classified as pasteurizedpasteurized. ​(a) Two cheesescheeses are chosen at random. What is the probability that both cheesescheeses are pasteurizedpasteurized​? ​(b) NineNine cheesescheeses are chosen at random. What is the probability that all ninenine cheesescheeses are pasteurizedpasteurized​? ​(c) What is the probability that at least one of ninenine randomly selected cheesescheeses is raw dash milkraw-milk​? Would it be unusual that at least one of ninenine randomly selected cheesescheeses is raw dash milkraw-milk​?
Mathematics
1 answer:
Volgvan3 years ago
3 0
Yes. Yes it is. Thanks for the awesome question.
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The amount of garbage, G produced by a city with population p is given by G = f(p). G is measured in tons per week, and p is mea
barxatty [35]
Alright, so this is simple.

P= 50,000 or 50 thousands

G= 13 Tons

The variable f isn't known.

So your equation would be 13 = 50 (f), if you were to put your known variables in the equation.

If you were to find variable f, you would divide 13 tons by 50,000 to get 0.00026 or in scientific notation: 2.6 x 10 (exponent(s):-4)



 

5 0
3 years ago
For each sequence write an explicit formula 96,48,24,12,6
STALIN [3.7K]
a_1=96;\ a_2=48;\ a_3=24;\ a_4=12;\ a_5=6\\\\a_1=a_2:2\to96:2=48\\a_2=a_3:2\to48:2=24\\a_3=a_2:2\to24:2=12\\a_4=a_3:2\to12:2=6\\\\therefore\\\\a_n=96:2^{n-1}=\frac {96}{2^{n-1}}\\\\check:\\a_1=\frac{96}{2^{1-1}}=\frac{96}{1^0}=96\\a_2=\frac{96}{2^{2-1}}=\frac{96}{2^1}=\frac{96}{2}=48\\a_3=\frac{96}{2^{3-1}}=\frac{96}{2^2}=\frac{96}{4}=24\\\vdots
8 0
3 years ago
HELPPP!!!!!!!!!!!!!! meeee ok so there are 12 boys and 8 girls in the french club. what is the ratio of boys to girls.
san4es73 [151]

Answer:

3:2

Step-by-step explanation:

The ratio of boys to girls will be 12:8

But, this can be simplified, since both numbers are divisible by 4.

12/4 = 3

8/4 = 2

So, the simplified ratio of boys to girls is 3:2

5 0
3 years ago
Read 2 more answers
The capacity of jose's vase is 2419 milliliters of water. he poured 1 liter 299 milliliters of water into the empty vase. then,
gogolik [260]
One liter is 1,000 ml.  plus 299 ml.  is 1,299 ml.  plus the additonal 398 ml. is 1,697 ml.  which is 722 ml.  less than the total volume. (722 ml. of water can still be added.)
3 0
3 years ago
The half-life of the isotope Osmium-183 is 12 hours. Choose the equation below that gives the remaining mass of Osmium-183 in gr
raketka [301]

The given equations are incomprehensible, I'm afraid...

You're given that osmium-183 has a half-life of 12 hours, so for some initial mass <em>M</em>₀, the mass after 12 hours is half that:

1/2 <em>M</em>₀ = <em>M</em>₀ exp(12<em>k</em>)

for some decay constant <em>k</em>. Solve for this <em>k</em> :

1/2 = exp(12<em>k</em>)

ln(1/2) = 12<em>k</em>

<em>k</em> = 1/12 ln(1/2) = - ln(2)/12

Now for some starting mass <em>M</em>₀, the mass <em>M</em> remaining after time <em>t</em> is given by

<em>M</em> = <em>M</em>₀ exp(<em>kt </em>)

So if <em>M</em>₀ = 590 g and <em>t</em> = 36 h, plugging these into the equation with the previously determined value of <em>k</em> gives

<em>M</em> = 590 exp(36<em>k</em>) = 73.75

so 73.75 ≈ 74 g of Os-183 are left.

Alternatively, notice that the given time period of 36 hours is simply 3 times the half-life of 12 hours, so 1/2³ = 1/8 of the starting amount of Os-183 is left:

590/8 = 73.75 ≈ 74

6 0
3 years ago
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