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4 years ago

6

Addition of _____________ to pure water causes the least increase in conductivity. A) weak bases B) acetic acid C) ionic compoun

ds D) organic molecules

2 answers:

geniusboy [140]4 years ago

8 0

Answer:

D

Explanation:

Water in itself is a bad conductor of electricity. Any compound that dissociates in water into ions and charged molecules, will increase conductivity of water. In this case ionic compounds weak basis and acids will put in free ions into the water. The ions can pass electricity because they are attracted to respective poles of electricity depending on their charges. In water, these ions are free moving unlike when they are immobilized in their lattice in solid form.

Organic compounds are mainly made of covalent bonds (around carbon) hence do not dissociate in water.

Mariana [72]4 years ago

3 0

Answer:

the answer is c

Explanation:

i just took it on usatp and its c

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8090 [49]

Answer:

Before:

$p_{truck}=16400\ kg.m/s$

$p_{car}=10000\ kg.m/s$

After:

$p_{truck}=8000\ kg.m/s$

$p_{car}=8400\ kg.m/s$

$v_{fcar}=8.4\ m/s$

$F=9333.33 \ Nw$

Explanation:

<u>Conservation of Momentum</u>

Two objects of masses m1 and m2 moving at speeds v1o and v2o respectively have a total momentum of

$p_1=m_1v_{1o}+m_2v_{2o}$

After the collision, they have speeds of v1f and v2f and the total momentum is

$p_2=m_1v_{1f}+m_2v_{2f}$

Impulse J is defined as

$J=F.t$

Where F is the average impact force and t is the time it lasted

Also, the impulse is equal to the change of momentum

$J=\Delta p$

As the total momentum is conserved:

$p_1=p_2$

$m_1v_{1o}+m_2v_{2o}=m_1v_{1f}+m_2v_{2f}$

We can compute the speed of the second object by solving the above equation for v2f

$\displaystyle v_{2f}=\frac{ m_1v_{1o}+m_2v_{2o} -m_1v_{1f} }{ m_2 }$

The given data is

$m_1=2000\ kg$

$m_2=1000\ kg\\v_{1o}=8.2\ m/s\\v_{2o}=0\ m/s\\v_{1f}=4\ m/s$

a) The impulse will be computed at the very end of the answer

b) Before the collision

$p_{truck}=2000\cdot 8.2=16400\ kg.m/s$

$p_{car}=1000\cdot 0=0\ kg.m/s$

c) After collision

$p_{truck}=2000\cdot 4=8000\ kg.m/s$

Compute the car's speed:

$\displaystyle v_{2f}=\frac{ 16400+0 -8000 }{ 1000 }$

$v_{2f}=8.4\ m/s$

And the car's momentum is

$p_{car}=1000\cdot 8.4=8400\ kg.m/s$

The Impulse J of the system is zero because the total momentum is conserved, i.e. \Delta p=0.

We can compute the impulse for each object

$J_1=\Delta p_1=2000(4-8.2)=-8400 \N.s$

The force can be computed as

$\displaystyle F=\frac{J}{t}=-\frac{8400}{0.9}=-9333.33 \ Nw$

The force on the car has the same magnitude and opposite sign

7 0

4 years ago

A 11.7-Ω resistor is made from a coil of copper wire whose total mass is 13.5 g . The resistivity of copper is 1.68×10−8Ω⋅m, the

Andrej [43]

Answer:

a) d = 7.62 10⁻⁶ m, b) l = 3.25 10⁴ m

Explanation:

Resistance is expressed by the formula

R = ρ l / A (1)

density is defined by

density = m / V

the volume of a wire is the cross section by the length

V = A l

we substitute

density = m / A l

A = m / density l

we substitute in 1

R = ρ l density l / m

R =ρ density l² / m

l = √ (R m /ρ density)

let's calculate the cable length

l = √(11.7 13.5 10⁻³ / (1.68 10⁻⁸ 8.9 10³))

l = √(10.56 10⁸)

l = 3.25 10⁴ m

now we can find the cable diameter with the density equation

A = m / density l

A = 13.5 10⁻³ / (8.9 10³ 3.25 10⁴)

A = 4,557 10⁻¹¹ m²

the area of the circle is

A = π r² = π d² / 4

d = √ (4A /π)

d = √ (4 4,557 10⁻¹¹/π)

d = 7.62 10⁻⁶ m

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3 years ago

Three point charges are fixed in place in a right triangle, as shown in the figure.

8090 [49]

Oh gosh oh I see it in my life face and

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3 years ago

how to use GRASS to answer this question: What voltage produces a current of 500A with a resistance of 50 ohms?

Pavel [41]

Answer:

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3 years ago

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olga_2 [115]

Answer:

combination of strength and speed

Explanation:

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3 years ago