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Basile [38]
3 years ago
12

A car moving at 16.0 m/s, passes an observer while its horn is pressed. the velocity of sound is 343 m/s and the frequency of th

e sound of the car’s horn is 583 hz. if the car is coming toward you, what frequency would you hear?
Physics
1 answer:
Arada [10]3 years ago
5 0
We are asked to solve for the frequency heard when a car is coming towards the observer. The car is moving at 16 m/s and the velocity of the sound is 343 m/s where the car horns at 583 Hz. We will use Doppler's Effect formula in calculating the unknown frequency such that the solution is shown below:
Fl = (V + Vl) * Fs / (V - Vs)
FL = (343 + 0)*583 / (343 - 16)
FL = 611. 53 Hertz

The answer for the frequency of the observer is 611.53 hertz.
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A standing wave of the third overtone is induced in a stopped pipe, 2.5 m long. The speed of sound is The frequency of the sound
NemiM [27]

Answer:

f3 = 102 Hz

Explanation:

To find the frequency of the sound produced by the pipe you use the following formula:

f_n=\frac{nv_s}{4L}

n: number of the harmonic = 3

vs: speed of sound = 340 m/s

L: length of the pipe = 2.5 m

You replace the values of n, L and vs in order to calculate the frequency:

f_{3}=\frac{(3)(340m/s)}{4(2.5m)}=102\ Hz

hence, the frequency of the third overtone is 102 Hz

8 0
3 years ago
En un m.A.S. La amplitud tiene un valor de 10 centimetros y el periodo es de 2 segundos calcular el valor de la velocidad de 0.8
Ivanshal [37]

Answer:

v1=18.46m/s

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Explanation:

We know that

A=10cm\\T=2s

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we can calculate w by using

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Hence, we have that

x=10cm*cos(\pi t)\\

the speed will be

v=-\omega*Asin(\omega t)\\|v(0.8)|=|\pi*10cm*sin(\pi *0.8)|=18.46\frac{cm}{s}\\|v(1.4)|=|\pi*10cm*sin(\pi *1.4)|=29.8\frac{cm}{s}

hope this helps!

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aliya0001 [1]
A seems to be correct
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astraxan [27]

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