The distance traveled by the scooter driver from 9:00 to 11:00 am is

snow_lady [41]

politics. Famous possible eg is of Werner Heisenberg in WW2. He delayed German attempt to build a nuclear bomb. US did build one ... hiroshima and nagasaki.

debbie may have got skilfully lucky by trial and error

6 0

3 years ago

Read 2 more answers

What is the mass of a baseball that has a kinetic energy of 105 J and is traveling at 10 m/s?

kkurt [141]

Answer:

$\boxed {\boxed {\sf 2.1 \ kilograms}}$

Explanation:

Kinetic energy is the energy an object possesses due to motion. The formula 1/2 the product of mass and the squared velocity.

$E_k=\frac{1}{2} mv^2$

We know the baseball's kinetic energy is 105 Joules. It is also traveling at a velocity of 10 meters per second. `

First, convert the units of Joules to make unit cancellation easier later in the problem. 1 Joule (J) is equal to 1 kilogram square meter per square second (kg*m²/s²). The baseball's kinetic energy of 105 J is equal to 105 kg*m²/s².

Now we know 2 values:

$E_k= 105 \ kg*m^2/s^2$

$v= 10 \ m/s$

Substitute these values into the formula.

$105 \ kg*m^2/s^2= \frac{1}{2} m (10 \ m/s)^2$

Now we need to solve for m, the mass. Solve the exponent.

(10 m/s)²= 10 m/s * 10 m/s = 100 m²/s²

$105 \ kg *m^2/s^2 = \frac{1}{2} m (100 \ m^2/s^2)$

Multiply on the right side.

$105 \ kg *m^2/s^2 = m (\frac{1}{2} * 100 \ m^2/s^2)$

$105 \ kg *m^2/s^2 = m (50 \ m^2/s^2)$

The variable, m, is being multiplied by 50 square meters per square second. The opposite of multiplication is division, so we divide both sides by that value.

$\frac {105 \ kg *m^2/s^2 }{50 \ m^2/s^2}= \frac{ m (50 \ m^2/s^2)}{50 \ m^2/s^2}$

$\frac {105 \ kg *m^2/s^2 }{50 \ m^2/s^2}= m$

The units of square meter per square second will cancel out.

$\frac {105 }{50} \ kg= m$

$2.1 \ kg=m$

The mass of the baseball is <u>2.1 kilograms. </u>

5 0

3 years ago

Which describes increasing the efficiency of energy resource

vova2212 [387]

Making cars that get better gas mileage

5 0

4 years ago

When two kinds of pulleys are used together the system is called

jekas [21]

They are called fixed and movable pulleys

3 0

3 years ago

A square plate of copper with 50.0-cm sides has no net charge and is placed in a region of a uniform electric field of 80.0 kN/C

torisob [31]

Answer:

σ = ±708 nC/m²

Q = ±177 nC

Explanation:

given data

Side of copper plate L = 50 cm

Electric field, E = 80 kN/C

solution

we get here Charge density,σ that is express as

σ = E x ε₀ ....................1

here ε₀ is Permittivity of free space that is 8.85 x 10⁻¹² C²/Nm²

so put value in eq1we get

σ = 80 x 10³ x 8.85 x 10⁻¹²

σ = 708 x 10⁻⁹ C/m²

σ = 708 nC/m²

and

now we get here total change on each faces

Q = σ A ...............2

Q = 708 x 10⁻⁹ x (0.50)²

Q = 177 nC

3 0

3 years ago