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To solve this problem we will apply the concepts related to the electric field. This is defined as the product between the angular frequency, the number of turns of the body (solenoid in this case) the magnetic field and the sine of the angular frequency and time. Mathematically this can be described as

Here,
= Angular frequency
N = Number of turns
B = Magnetic field
The emf has its maximum value when 
Thus the amplitude of the emf is

When number of turns of armature, area and applied magnetic field remains constant, induced emf is proportional to angular speed.

Further it can be written as follows,




Therefore the maximum amplitude of induced emf when armature rotates at 10.0rad/s is 18V
<span>This projectile has been thrown in an oblique movement, so it’s moving in x and in y at the same time. Vy varies due to gravity, and Vx is a constant as there is no gravity in the horizontal direction. In order to calculate Vx, you have to use the angle:
Vx=V*cosa=12m/s*cos(14.2)= 11.6m/s
So now you should use Vx the same way it is used in a uniform linear movement.
d=v*t
dx=vx*t
t=dx/vx=7m/(11.6m/s)=0.603s</span>