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DanielleElmas [232]
3 years ago
10

Two positive point charges repel each other with force 0.36 N when their separation is 1.5 m. What force do they exert on each o

ther when their separation is 1.0 m
Physics
1 answer:
egoroff_w [7]3 years ago
6 0
The answer is: 0.81

I hope this helps :)
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What is limiting friction​
Fantom [35]

Answer:

Explanation:

As you start increasing the force on an object from 0 N it the object will stay at rest and at a certain magnitude of force the object will start moving. The friction acting on that object is known as limiting frictional force. The magnitude of this frictional force is equal to the force that we apply on the object as it just start to move.

It's important to note that the limiting frictional force is the largest frictional force act on that object in the above explained process. The dynamic frictional force ( the frictional force acting on an moving object.) is always less than the limiting frictional force.

5 0
3 years ago
A parallel-plate capacitor has plates of area 0.40 m2 and plate separation of 0.20 mm. The capacitor is connected to a 9.0 V bat
mafiozo [28]

Answer:

a) E = 4.5*10⁴ V/m

b) C= 17.7 nF

c) Q = 159. 3 nC  

Explanation:

a)

  • By definition, the electric field is the electrostatic force per unit charge, and since the potential difference between plates is just the work done by the field, divided by the charge, assuming a uniform electric field, if V is the potential difference between plates, and d is the separation between plates, the electric field can be expressed as follows:

       E = \frac{V}{d} = \frac{9.0V}{2*10-4m} =4.5 * 10e4 V/m (1)

b)

  • For a parallel-plate capacitor, applying the definition of capacitance as the quotient between the charge on one of the plates and the potential difference between them, and assuming a uniform surface charge density σ, we get:

       Q = \sigma* A (2)

        From (1), we know that V = E*d, but at the same time, applying Gauss'

        Law at a closed surface half within the plate, half outside it , it can be

        showed than E= σ/ε₀, so finally we get:

       C = \frac{Q}{V} =\frac{\sigma*A}{E*d}  = \frac{\sigma*A}{\frac{\sigma}{\epsilon_{o} } d} =\frac{\epsilon_{0}*A}{d} = \frac{8.85e-12F/m*0.4m2}{2e-4m} = 17.7 nF (3)

c)    

  • From (3) we can solve for Q as follows:

       Q = C* V = 17.7 nF * 9.0 V = 159.3 nC  (4)

6 0
3 years ago
What is the resistance of a toaster that uses 2A when connected to a 120V power source?
denis23 [38]

Answer:

60 ohms

Explanation:

From Ohm's Law:

V = IR

Where V = 120volts

I = 2A

R = ?

Note that R,V and I represents resistance, voltage and current respectively.

Substituting the above values into the formula.

V = IR

120v = 2×R

120= 2R

Making R the subject

R =120/2

R = 60 ohms

Hence the resistance of the toaster will be 60 ohms.

8 0
3 years ago
Cual es la fuerza electrica sobre el electrón (-1.6 x 10¹⁹c) de un atomo de hidrógeno ejercida por el protón (1.6 x 10¹⁹c)? Supó
kkurt [141]

Answer:

La  fuerza eléctrica es -8.2*10⁻⁸ N

Explanation:

El enunciado correcto es: <em>¿Cuál es la fuerza eléctrica sobre el electrón (-1.6 x 10⁻¹⁹c) de un átomo de hidrógeno ejercida por el protón (1.6 x 10⁻¹⁹c)? Supóngase que la distancia entre el electrón y el protón es de 5.3 x 10⁻¹¹ m</em>

Entre dos o más cargas aparece una fuerza denominada fuerza eléctrica. Su valor depende del valor de las cargas y de la distancia que las separa, mientras que su signo depende del signo de cada carga. Las cargas del mismo signo se repelen entre sí, mientras que las de distinto signo se atraen.

La fuerza eléctrica con la que se atraen o repelen dos cargas puntuales en reposo es directamente proporcional al producto de las mismas e inversamente proporcional al cuadrado de la distancia que las separa:

F=K*\frac{q1*q2}{d^{2} }

donde:

  • F es la fuerza eléctrica de atracción o repulsión. En el Sistema Internacional (S.I.) se mide en Newtons (N).
  • q1 y q2 son lo valores de las dos cargas puntuales. En el S.I. se miden en Culombios (C).
  • d es el valor de la distancia que las separa. En el S.I. se mide en metros (m).
  • K es una constante de proporcionalidad llamada constante de la ley de Coulomb. Depende del medio en el que se encuentren las cargas. Para el vacío K tiene un valor aproximadamente de 9*10⁹ \frac{N*m^{2} }{C^{2} }.

En este caso:

  • F=?
  • K= 9*10⁹ \frac{N*m^{2} }{C^{2} }
  • q1= -1.6*10⁻¹⁹ C
  • q2= 1.6*10⁻¹⁹ C
  • d= 5.3*10⁻¹¹ m

Reemplazando:

F=9*10^{9} \frac{N*m^{2} }{C^{2} }*\frac{(-1.6*10^{19} C)*(1.6*10^{19} C)}{(5.3*10^{-11} )^{2} }

Resolviendo:

F= -8.2*10⁻⁸ N

<u><em>La  fuerza eléctrica es -8.2*10⁻⁸ N</em></u>

6 0
4 years ago
HEY CAN ANYONE PLS ANSWER DIS!!!!!!
antiseptic1488 [7]

Answer:

I think That All the atoms of a given element are identical in that they have the same number of protons

Explanation:

3 0
3 years ago
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