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Hunter-Best [27]
3 years ago
8

Why can't dna, rna, and proteins be used to compare only dead organisms?

Biology
1 answer:
mart [117]3 years ago
8 0

I am not too sure, but I believe it is because DNA is actually apart of living organisms along with Protein. So it can't only be compared with dead organisms but they can be living.

<u>Hope this helps!</u>

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What was the goal of the EPA Chesapeake Bay Study?
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Answer:

the 1987 Chesapeake bay agreement set the first numeric goals to reduce pollution and restore the bay ecosystem

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7. What is the relationship between the amount of greenhouse gasses in the atmosphere and the average global temperature
kompoz [17]

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More heat in the atmosphere, less absorption of greenhouse gases on Earth, and solar and volcanic activity may contribute to an increase in global average surface temperatures.

Explanation:

8 0
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Please help
butalik [34]

The right answer is: The antibodies mistakenly identify the cells as foreign material.

The role of an antibody is to recognize a foreign antigen in order to neutralize it. They can achieve this thanks to the great specificity of their paratope, which recognizes only a very precise part of the antigen: the epitope. As soon as an antibody recognizes an epitope, the B lymphocyte that codes for that specific antibody multiplies and matures in order to synthesize the same antibodies, useful in large quantities.

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8 0
2 years ago
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New oceanic lithosphere is unable to form at mid-ocean ridges. Please select the best answer from the choices provided T F
miss Akunina [59]
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8 0
3 years ago
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In humans, MN blood types are determined by an autosomal gene with two alleles: LM and LN. In one population of 592 people, ther
RoseWind [281]

Answer:

148

Explanation:

According to Hardy-Weinberg equilibrium,

p + q = 1

p² + 2pq + q² = 1 where,

p = frequency of dominant allele

q = frequency of recessive allele

p² = frequency of homozygous dominant genotype

2pq = frequency of heterozygous genotype

q² = frequency of homozygous recessive genotype

Here,

Total population = 592

Number of NN people = 148

Frequency of N blood group or NN genotype (q²) = 148/592 = 0.25

q = √0.25 = 0.5

p = 1 - q

= 1 - 0.5 = 0.5

Hence, p = 0.5

Frequency of MM genotype = p² = 0.25

Number of people with MM genotype = 0.25*592 = 148

Hence, 148 people will have MM genotype or M blood group.

5 0
3 years ago
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