How easy! Just list all the factors that add up to ten.
10 + 0
9 + 1
8 + 2
7 + 3
6 + 4
5 + 5
Which ones match the requirements?
With 2 dices we have all 6x6=36 ways.
But for two conditions: sum 8 and both even numbers, we have only: (2;6), (6;2), (4;4). That's all.
And the probability is 3/36= 1/12
Have fun
The denominator is the one on the bottom so 9 is the denominator the top is the numerator
The missing value is 6 so 2/5 = 6/15
