Answer:
The required confidence interval is (3.068,4.732)
Step-by-step explanation:
Consider the provided information.
He plans to use a 90% confidence interval. He surveys a random sample of 50 students. The sample mean is 3.90 alcoholic drinks per week. The sample standard deviation is 3.51 drinks and wants to construct 90% confidence interval.
Thus, n=50, 
=3.90 σ=3.51
Now find degree of freedom.
The confidence level is 90% and df=49
Therefore,
Now by using t distribution table look at 49 df and alpha level on 0.05.
Calculate SE as shown:
Now multiply 1.67653 with 0.4964
Therefore, the marginal error is: 1.67653 × 0.4964≈ 0.832
Now add and subtract this value in given mean to find the confidence interval.
Hence, the required confidence interval is (3.068,4.732)
<span>Suppose 2x + y = 15 -----eq 1
. x + 3y = 20 -----eq 2.
Multiplying eq (1) by 1 and (2) by 2 and subtracting the result
We have: 2x + y = 15 and 2x +6y =40.If we subtract, we have y - 6y = 15 - 40.
So we have -5y = -25. y is 5. Substiting into eq (1), we have 2x + 5 = 15. 2x = 15-5 =10 Hence X =5.Hence option B is the correct option.</span>
Answer:
The LCM for 4 and 8 is 8. Add both numerator and rewrite it in a single form. By using LCM method, 7/8 is the equivalent fraction by adding 3/4 and 1/8.
Hope This Helps!!! Have a great day!
<3<3
Answer: 500 votes
Step-by-step explanation:
This can be shown by this formula.
300 is 60% of x. So if u can find the 100% by taking 300 and multiplying it by 100 which would be the 100% and dividing it by 60 which would be the 60%. The number that you get is how many didn't vote for Denise. Now just add these which would be 300+200 which would give you the answer above.
EF for sure u got to really pay attention to the inches
