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3 years ago

I’ll mark bralyist to the first correct answer If f(x) = 1/4 x + 14, then F^-1 (x) =

Mathematics

1 answer:

bagirrra123 [75]3 years ago

7 0

Answer:

1/4

Step-by-step explanation:

dy/dx(1/4x + 14)=1/4

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amy makes $7.50 an hour working at restaurant.her paycheck shows that she worked 15 hours over the past week.how much did amy ma

Vanyuwa [196]

The answer is 7.50×15= 112.50

6 0

3 years ago

For her presentation on the Wonders of the World, Mary baked a square pyramid-shaped cake as pictured below. The slant height of

mihalych1998 [28]

Answer:

$V=196in^3$

Step-by-step explanation:

The volume of a pyramid is:

$V=\frac{A_{b}h}{3}$

where $A_{b}$ is the area of the base and $h$ is the height (the perpendicular measurement between base and highest point, not the slant height)

Since the base is a square, the area is given by:

$A_{b}=l^2$

where $l$ is the length of the side: $l=8in$ , thus:

$A_{b}=(8in)^2\\A_{b}=64in^2$

Now we need to find the height, for this we use the right triangle that forms with half of a square side (8in/2 = 4in), the slant height (10in), and the height.

In this right triangle, the slant height is the hypotenuse, the leg 1 is the unknown height, and leg 2 is half of the square side.

Using pythagoras:

$hypotenuse^2=leg1^2+leg2^2$

substituting our values, and indicating that leg 1 is height h:

$(10in)^2=h^2+(4in)^2$

$100in^2=h^2+16in^2$

and solving for the height:

$h^2=100in^2-16in^2\\h^2=84in^2\\h=\sqrt{84in^2}\\ h=9.165in$

and finally we calculate the volume using this height and the area of the base:

$V=\frac{A_{b}h}{3}$

$V=\frac{(64in^2)(9.165in)}{3} \\V=195.5in^3$

rounding to the nearest cubic inch: $V=196in^3$

4 0

3 years ago

Nancy bought 5 1/2 pounds of apples and oranges. If she bought 1 2/3 pounds of apples, which of the following equations could be

poizon [28]

Answer:

5 1/2-p=1 2/3

Step-by-step explanation:

let p represent the weight of the oranges!

6 0

3 years ago

Kindly answer this one. Thank you.

steposvetlana [31]

Answer:

See below.

Step-by-step explanation:

I'm assuming these questions are about the Midline Theorem (segment AL joins the midpoints of the non-parallel sides.

♦ The midline's length is the average of the lengths of the top and bottom parallel sides.

$AL=\frac{OR+CE}{2}$

Use this equation and substitute values given in each problem, then solve for the missing information.

1. AL = x, CE = 9, OR = 5

$x=\frac{9+5}{2}=7$

2. AL = <em>m</em> - 4, CE = 15, OR = 17

$m-4=\frac{15+17}{2}=16\\\\m-4=16\\\\\\m=20\\\\AL=20-4=16$

3. OR = y + 5, AL = 15, CE = 18

$15=\frac{(y+5)+18}{2}\\\\15=\frac{y+23}{2}\\\\30=y+23\\\\7=y\\\\OR = 7+5=12$

4 0

3 years ago

I really don’t get this at all. kinda need help

rewona [7]

Same . It’s not giving me a lot of information!!

5 0

3 years ago