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Luden [163]
3 years ago
9

A new cruise ship line has just launched 3 new​ ships: the Pacific​ Paradise, the Caribbean​ Paradise, and the Mediterranean Par

adise. The Caribbean Paradise has 24 more deluxe staterooms than the Pacific Paradise. The Mediterranean Paradise has 29 fewer deluxe staterooms than three times the number of deluxe staterooms on the Pacific Paradise. Find the number of deluxe staterooms for each of the ships if the total number of deluxe staterooms for the three ships is 735.
Mathematics
1 answer:
kotegsom [21]3 years ago
7 0
So you have to set up an equation that looks like this:
D x 3-29+24=735

Now you have to solve the equation yourself becuase that is easy.


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Need help figuring out A=
Bogdan [553]
Better labeling so I can understand.
5 0
3 years ago
In the diagram abc=adb=90, ad=p and dc=q. Use similar triangles to show that x2=pz<br> plzz anyoneee
kramer

Answer:

By comparing the ratios of sides in similar triangles ΔABC and ΔADB,we can say that x^{2} =pz

Step-by-step explanation:

Given that ∠ABC=∠ADC, AD=p and DC=q.

Let us take compare Δ ABC and  Δ ADB in the attached file , ∠A is common in both triangles

                                                                     and given ∠ABC=∠ADB=90°

Hence using AA postulate, ΔABC ≈ ΔADB.

Now we will equate respective side ratios in both triangles.

\frac{AB}{AC}= \frac{AD}{AB}=\frac{BD}{BC}

Since we don't know BD , BC let us take first equality and plugin the variables given in respective sides.

\frac{x}{z}= \frac{p}{x}

Cross multiply

x^{2}=pz

Hence proved.


7 0
3 years ago
b. Tyler practiced the clarinet for 64% as much time as Han practiced the piano. How long did he practice?
Ksivusya [100]

Answer: 48 minutes

Step-by-step explanation:

Han spent 75 minutes practicing the piano.

Tyler spent only 64% as much as that. How long did Tyler practice:

= 75 * 64%

= 48 minutes

6 0
3 years ago
Let ​ f(x) = 4(x^2) - 3x
posledela

Answer:

(f+g)(x)=5x²-4x+3

(f-g)(x)=3x²-2x+3

(fg)(x)=4x^4-7x^3+15x^2-9x

\frac{f}{g}(x) =\frac{4x^2-3x}{x^2-x+3}

Step-by-step explanation:

Given that,

f(x)=4x²-3x

g(x)=x²-x+3

(f+g)(x)

=f(x)+g(x)

=4x²-3x+x²-x+3

=(4x²+x²)+(-3x-x)+3   [ combined the like terms]

=5x²-4x+3

(f-g)(x)

=f(x)-g(x)

=4x²-3x-(x²-x+3)

=4x²-3x-x²+x-3

=(4x²-x²)+(-3x+x)-3   [ combined the like terms]

=3x²-2x+3

(fg)(x)

=f(x).g(x)

=(4x²-3x).(x²-x+3)

=4x²(x²-x+3)-3x(x²-x+3)

=4x^4-4x^3+12x^2-3x^3+3x^2-9x

=4x^4+(-4x^3-3x^3)+(12x^2+3x^2)-9x

=4x^4-7x^3+15x^2-9x

\frac{f}{g}(x)

=\frac{f(x)}{g(x)}

=\frac{4x^2-3x}{x^2-x+3}

7 0
3 years ago
What is the greatest possible product of a 2 digit number and a 1 digit number?
ss7ja [257]
99 x 9 = 891 I think
5 0
3 years ago
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