Better labeling so I can understand.
Answer:
By comparing the ratios of sides in similar triangles ΔABC and ΔADB,we can say that 
Step-by-step explanation:
Given that ∠ABC=∠ADC, AD=p and DC=q.
Let us take compare Δ ABC and Δ ADB in the attached file , ∠A is common in both triangles
and given ∠ABC=∠ADB=90°
Hence using AA postulate, ΔABC ≈ ΔADB.
Now we will equate respective side ratios in both triangles.

Since we don't know BD , BC let us take first equality and plugin the variables given in respective sides.

Cross multiply

Hence proved.
Answer: 48 minutes
Step-by-step explanation:
Han spent 75 minutes practicing the piano.
Tyler spent only 64% as much as that. How long did Tyler practice:
= 75 * 64%
= 48 minutes
Answer:
(f+g)(x)=5x²-4x+3
(f-g)(x)=3x²-2x+3
(fg)(x)

Step-by-step explanation:
Given that,
f(x)=4x²-3x
g(x)=x²-x+3
(f+g)(x)
=f(x)+g(x)
=4x²-3x+x²-x+3
=(4x²+x²)+(-3x-x)+3 [ combined the like terms]
=5x²-4x+3
(f-g)(x)
=f(x)-g(x)
=4x²-3x-(x²-x+3)
=4x²-3x-x²+x-3
=(4x²-x²)+(-3x+x)-3 [ combined the like terms]
=3x²-2x+3
(fg)(x)
=f(x).g(x)
=(4x²-3x).(x²-x+3)
=4x²(x²-x+3)-3x(x²-x+3)





