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svetoff [14.1K]
3 years ago
5

Solve 5(2y+1)=4y+10. this is for algebra 1

Mathematics
2 answers:
jolli1 [7]3 years ago
5 0

Answer:

y=5/6\approx0.83

Step-by-step explanation:

So we have the equation:

5(2y+1)=4y+10

First, let's distribute the left side of our equation:

5(2y)+5(1)=4y+10

Multiply:

10y+5=4y+10

Now, let's isolate the y-variable. Subtract 4y from both sides:

(10y+5)-4y=(4y+10)-4y

The right side cancels. Subtract on the left. So:

6y+5=10

Now, subtract 5 from both sides:

(6y+5)-5=(10)-5

The left side cancels. Subtract on the right:

6y=5

Now, divide both sides by 6. So:

\frac{6y}{6}=\frac{5}{6}

The left will cancel. Therefore:

y=5/6\approx0.83

And we're done!

Lesechka [4]3 years ago
5 0
5(2y+1)=4y+10(multiply 5 to 2y and 1)
10y+5=4y+10(subtract 5 from 5 and 10)
10y=4y+5(subtract 4y from 4y and 10y)
6y=5(divide 6 by 6y and 5)
y=0.83

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Answer:

32 x p/100 = 40

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(reason why you multiply by 100 is because opposite of division is multiplication and we multiply the number "100" because we always multiply the denominator to both sides when having a fraction so you can solve for p or whatever. And that means p/100 x 100 it means p because since p is not a known value we consider 1/100 x 100 = 1, a variable by itself means 1 so you could just put p by itself next to the number its multiplied by which is 32 so it would be 32p because your multiplying both and the opposite of that would be dividing by 32 on both sides because you are getting rid of the 32 so therefore you will be left with: X = 125)

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