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svetoff [14.1K]
3 years ago
5

Solve 5(2y+1)=4y+10. this is for algebra 1

Mathematics
2 answers:
jolli1 [7]3 years ago
5 0

Answer:

y=5/6\approx0.83

Step-by-step explanation:

So we have the equation:

5(2y+1)=4y+10

First, let's distribute the left side of our equation:

5(2y)+5(1)=4y+10

Multiply:

10y+5=4y+10

Now, let's isolate the y-variable. Subtract 4y from both sides:

(10y+5)-4y=(4y+10)-4y

The right side cancels. Subtract on the left. So:

6y+5=10

Now, subtract 5 from both sides:

(6y+5)-5=(10)-5

The left side cancels. Subtract on the right:

6y=5

Now, divide both sides by 6. So:

\frac{6y}{6}=\frac{5}{6}

The left will cancel. Therefore:

y=5/6\approx0.83

And we're done!

Lesechka [4]3 years ago
5 0
5(2y+1)=4y+10(multiply 5 to 2y and 1)
10y+5=4y+10(subtract 5 from 5 and 10)
10y=4y+5(subtract 4y from 4y and 10y)
6y=5(divide 6 by 6y and 5)
y=0.83

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Step-by-step explanation:

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Replacing in the other equation we should get the same result.

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Evaluate the function f (x)= x squared -4x+1 at the given values of the independent variable and simplify.
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<h3>Given</h3>

... f(x) = x² -4x +1

<h3>Find</h3>

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... b) f(x+9)

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<h3>Solution</h3>

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b) f(x+9) = (x+9)² -4(x+9) +1

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c) f(-x) = (-x)² -4(-x) +1

... f(-x) = x² +4x +1

8 0
3 years ago
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