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3 years ago

Anybody know the answer?

Mathematics

2 answers:

Deffense [45]3 years ago

4 0

I think it should end up to be cos + cos

jeka57 [31]3 years ago

3 0

That equation would become :

[cosx*cosx +sinx*sinx], [cos^2(x)+sin^2(x)]

When adding the squares of a sin and cos, the answer is one. The is a trig identity you MUST memorize.

So : cos^2(x)+sin^2(x)=1

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Write an equivalent expression for 7a + 21

PSYCHO15rus [73]

7(a+3) this is the answer im pretty sure

4 0

4 years ago

Can someone help me

sertanlavr [38]

Answer: Around 38.2°

Step-by-step explanation:

Set ∠A = x & a = 15
Set ∠B = 27° & b = 11

Substitute them into the formula for the law of sines:

$\frac{sinA}{a} =\frac{sinB}{b} \\\\\frac{sinx}{15}=\frac{sin27}{11} \\$

Cross-multiply:

$11sinx=15sin27$

Solve for x:

$sinx=\frac{15sin27}{11} \\\\x=sin^{-1} (\frac{15sin27}{11})\\\\=38.2488$

3 0

3 years ago

Indicate the equation of the given line in standard form. The line through point (-3, 4) and perpendicular to a line that has sl

statuscvo [17]

To be perpendicular the product of the two slopes must equal -1.

2m/5=-1

2m=-5

m=-2.5

since y=mx+b we have so far

y=-2.5x+b, using point (-3,4) we can solve for b

4=-2.5(-3)+b

4=7.5+b

b=-3.5 so

y=-2.5x-3.5 We can multiply the whole equation by two so that the coefficients are integers...

2y=-5x-7 add 5x to both sides

5x-2y=-7

6 0

3 years ago

How to find the solution of |a-4|=3a-6

Anika [276]

For
|a|=b, solve for
a=b and a=-b

so

|a-4|=3a-6
solve
a-4=3a-6 and a-4=-(3a-6)

first one
a-4=3a-6
minus a from both sides
-4=2a-6
add 6 to both sides
2=2a
divide by 2
1=a

other

a-4=-(3a-6)
a-4=-3a+6
add 3a both sides
4a-4=6
add 4 to both sides
4a=10
divide by 4
a=10/4
a=5/2

a=5/2 and 1

6 0

4 years ago

Which statement about the polynomial function g(x) is true?

kakasveta [241]

Answer:

C) If the leading coefficient of g(x) is 1, all rational roots of g(x) = 0 must be integers.

Step-by-step explanation:

6 0

3 years ago