Answer: The required probability is 
Step-by-step explanation:
Since we have given that
Number of kids = 10
Number of kids in Team A = 5
Number of kids in Team B = 5
There are three kids in the group, Alex and his two best friends Jose and Carl.
So, number of favourable outcome is given by

Total number of outcomes is given by

So, the probability that Alex ends up on the same team with at least one of his two best friends is given by

Hence, the required probability is 
Given:
The population of continent of South America in 2010 is 395, 280, 204.
To find:
The closest estimate of this number.
Solution:
We have,

The approximate value of this number is

The scientific form of this value is

Therefore, the correct option is C.
Given

on the interval 0 ≤ x ≤ 7, for maximum value, f'(x) = 0.
Answer:
x=55 y=70
Step-by-step explanation:
Given,
x
2
+
x
2
1
=98
(x+
x
1
)
2
=x
2
+
x
2
1
+2
98+2=100
∴x+
x
1
=10
(x+
x
1
)
3
=x
3
+
x
3
1
+3(x+
x
1
)
x
3
+
x
3
1
+3(x+
x
1
)=1000
x
3
+
x
3
1
=1000−3(10)=