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3 years ago

3|2x+5|-9 = 0 solve the absolute value equation

Mathematics

1 answer:

Ronch [10]3 years ago

3 0

Answer:x=−1 or x=−4

Step-by-step explanation:

Let's solve your equation step-by-step.

3(|2x+5|)−9=0

Step 1: Add 9 to both sides.

3(|2x+5|)−9+9=0+9

3(|2x+5|)=9

Step 2: Divide both sides by 3.

3(|2x+5|)

|2x+5|=3

Step 3: Solve Absolute Value.

|2x+5|=3

We know either2x+5=3or2x+5=−3

2x+5=3(Possibility 1)

2x+5−5=3−5(Subtract 5 from both sides)

2x=−2

−2

(Divide both sides by 2)

x=−1

2x+5=−3(Possibility 2)

2x+5−5=−3−5(Subtract 5 from both sides)

2x=−8

−8

(Divide both sides by 2)

x=−4

Answer: x=−1 or x=−4

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Answer:

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Step-by-step explanation:

Given

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To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

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$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

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$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

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Hence:

$a(a'(d)) = a'(a(d)) = d$

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