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scoray [572]
3 years ago
13

3|2x+5|-9 = 0 solve the absolute value equation

Mathematics
1 answer:
Ronch [10]3 years ago
3 0

Answer:x=−1 or x=−4

Step-by-step explanation:

Let's solve your equation step-by-step.

3(|2x+5|)−9=0

Step 1: Add 9 to both sides.

3(|2x+5|)−9+9=0+9

3(|2x+5|)=9

Step 2: Divide both sides by 3.

3(|2x+5|)

3

=

9

3

|2x+5|=3

Step 3: Solve Absolute Value.

|2x+5|=3

We know either2x+5=3or2x+5=−3

2x+5=3(Possibility 1)

2x+5−5=3−5(Subtract 5 from both sides)

2x=−2

2x

2

=

−2

2

(Divide both sides by 2)

x=−1

2x+5=−3(Possibility 2)

2x+5−5=−3−5(Subtract 5 from both sides)

2x=−8

2x

2

=

−8

2

(Divide both sides by 2)

x=−4

Answer: x=−1 or x=−4

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Drupady [299]

Answer:

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Step-by-step explanation:

Given

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Solving (a): Write as inverse function

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To do this, we prove that:

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Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

Substitute \frac{d}{5} + \frac{3}{5} for d in  a(d) = 5d - 3

a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

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Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

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Hence:

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