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Mrac [35]
3 years ago
11

Determine the longest interval in which the given initialvalue problemis certainto have a unique twicedifferentiable solution. D

o not attempt to find the solutionty'' + 3y = t, y(1) = 1, y'(1) = 9
Mathematics
1 answer:
AlekseyPX3 years ago
6 0

Answer:

t_o = 3, so solution exists on (0,4).  

Step-by-step explanation:

Use Theorem

Divide equation with t(t — 4).

y''+[3/(t-4)]*y'+ [4/t(t-4)]*y=2/t(t-4)

p(t)=3/t-4—> continuous on (-∞, 4) and (4,∞)

q(t) = 4/t(t-4) —> continuous on (-∞,0), (0,4) and (4, ∞)

g(t) = 2/t(t-4)—> continuous on (-∞, 0), (0,4) and (4,∞)

t_o = 3, so solution exists on (0,4).  

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Can someone smart help me here?
V125BC [204]
The answer is 573

S is the three digit number.
h - a number of hundreds
t - a number of tens
o - a number of ones

S = 100h + 10t + o

<span>The last two digits add to make ten: t + o = 10
</span><span>The first and last digits add to make eight: h + o = 8
</span><span>The first two digits add to make twelve: h + t = 12

</span>t + o = 10          ⇒ o = 10 - t
h + o = 8           ⇒ o = 8 - h
_______
10 - t = 8 - h
h + t = 12          ⇒ h = 12 - t
_______
10 - t = 8 - (12 - t)
10 - t = 8 - 12 + t
10 - t = -4 + t
10 + 4 = t + t
2t = 14
t = 14/2 = 7
______

h = 12 - t = 12 - 7 = 5
______

o = 8 - h = 8 - 5 = 3

S =  100h + 10t + o
h = 5
t = 7
o = 3

S = 100*5 + 10*7 + 3
   = 500 + 70 + 3
   = 573
8 0
3 years ago
Someone answer this please, I’ll give you brainliest and your getting a lot of points.
ANTONII [103]

Answer:

Step-by-step explanation:

Recursive formula

tn = t_n-1 / 4

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t1 = 10240 / 4 = 2560

Explicit formula

tn = 10240 / 4^(n-1)

t4 = 10240 / 4^(4 - 1)

t4 = 10240 / 4^3

t4 = 10240 / 64

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t8 = 10240 / 4^7

t8 = 0,625

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2 years ago
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5 0
3 years ago
How do I do this I'm am really confused?
MrMuchimi
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4y-42 = 2y

From there you want to put the y onto one side:

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You want to balance the equation out and move the -42 onto the other side so you add it to both sides to get:

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Then divide both sides by 2 to get:

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Answer:

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