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2 years ago

Write y+7 = 2/3 (4x-6) in standard form using integers

Mathematics

1 answer:

Marrrta [24]2 years ago

4 0

9514 1404 393

Answer:

8x -3y = 33

Step-by-step explanation:

Multiply by 3 to eliminate the fraction. Then rearrange to standard form.

y +7 = 2/3(4x -6) . . . . . . . given

3(y +7) = 2(4x -6) . . . . . . . multiply by 3

3y +21 = 8x -12 . . . . . . . . eliminate parentheses

33 = 8x -3y . . . . . . . . . . add 12-3y to both sides

8x -3y = 33 . . . . . . . . . swap sides to put into standard form

_____

Standard form has mutually prime integer coefficients, the leading one being positive.

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3 years ago

Rewrite in simplest radical form square root of x times the fourth root of x. Show each step of your process.

Ipatiy [6.2K]

Answer:

$\sqrt[4] {x^3}$

Step-by-step explanation:

At this point, we can transform the square root into a fourth root by squaring the argument, and bring into the other root:

$\sqrt x \cdot \sqrt[4] x =\sqrt [4] {x^2} \cdot \sqrt[4] x = \sqrt[4]{x^2\cdot x} = \sqrt[4] {x^3}$

Alternatively, if you're allowed to use rational exponents, we can convert everything:

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2 years ago

How many edges does a tetrahedron have? 6 9 12 18

Jet001 [13]

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3 years ago

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lutik1710 [3]

Answer:

x = 15

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Sum the 3 given angles and equate to 180, that is

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3 0

3 years ago

Solve the system of equations. x+y=4 y=x^2 - 8x + 16 a) {(-3,7).(-4, 8)} b) [(4,0)} c) {(3,1),(4,0) d) {(3,7). (4.0)} e) none

Marysya12 [62]

Answer: The required solution of the given system is

(x, y) = (3, 1) and (4, 0).

Step-by-step explanation: We are given to solve the following system of equations :

$x+y=4~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\y=x^2-8x+16~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

From equation (i), we have

$x+y=4\\\\\Rightarrow y=4-x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)$

Substituting the value of y from equation (iii) in equation (ii), we get

$y=x^2-8x+16\\\\\Rightarrow 4-x=x^2-8x+16\\\\\Rightarrow x^2-8x+16-4+x=0\\\\\Rightarrow x^2-7x+12=0\\\\\Rightarrow x^2-4x-3x+12=0\\\\\Rightarrow x(x-4)-3(x-4)=0\\\\\Rightarrow (x-3)(x-4)=0\\\\\Rightarrow x-3=0,~~~~~~~x-4=0\\\\\Rightarrow x=3,~4.$

When, x = 3, then from (iii), we get

$y=4-3=1.$

And, when x = 4, then from (iii), we get

$y=4-4=0.$

Thus, the required solution of the given system is

(x, y) = (3, 1) and (4, 0).

8 0

3 years ago