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e-lub [12.9K]
3 years ago
14

Which property is illustrated by the statement? ^2 (-6/7) = (-6/7)^2

Mathematics
1 answer:
Murljashka [212]3 years ago
8 0
Communtive property of division
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These Questions is worth 20 Points. No Explanation Required.
avanturin [10]

13. five plus <em>y</em> equal to negative two. y = -7

14. eight plus <em>h</em> equal to twelve. h = 4

15. negative thirteen plus four equal <em>n</em>. n = -9

7 0
3 years ago
You are looking at the New York ball drop on New Year’s Eve at a distance of 100 m away from the base of the structure. If the b
Fofino [41]

The question is an illustration of related rates.

The rate of change between you and the ball is 0.01 rad per second

I added an attachment to illustrate the given parameters.

The representations on the attachment are:

\mathbf{x = 100\ m}

\mathbf{\frac{dy}{dt} = 2\ ms^{-1}} ---- the rate

\mathbf{\theta = \frac{\pi}{4}}

First, we calculate the vertical distance (y) using tangent ratio

\mathbf{\tan(\theta) = \frac{y}{x}}

Substitute 100 for x

\mathbf{y = 100\tan(\theta) }

\mathbf{\tan(\theta) = \frac{y}{100}}

Differentiate both sides with respect to time (t)

\mathbf{ \sec^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dy}{dt}}

Substitute values for the rates and \mathbf{\theta }

\mathbf{ \sec^2(\pi/4) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}

This gives

\mathbf{ (\sqrt 2)^2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}

\mathbf{ 2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}

Divide both sides by 2

\mathbf{ \frac{d\theta}{dt} = \frac{1}{100} }

\mathbf{ \frac{d\theta}{dt} = 0.01 }

Hence, the rate of change between you and the ball is 0.01 rad per second

Read more about related rates at:

brainly.com/question/16981791

8 0
2 years ago
A jeweler is dividing
Anuta_ua [19.1K]

Answer: OPTION D:  \frac{3}{32}

Step-by-step explanation:

By definiton, fractions have the following form:

\frac{a}{b}

Where "a" is called numerator and "b" is the denominator. The numerator and the denominator are Integers.

 In order to solve this exercise you need to remember de Division of fractions:

\frac{a}{b}\div\frac{d}{e}=\frac{a}{b}*\frac{e}{d}=\frac{a*e}{b*d}

In this case, according to the information given in the exercise, you know that \frac{3}{8}\ lb of rubies are divided into 4 lots.

Therefore, in order to calculate the weight in pounds of each lot, you need to divide \frac{3}{8}\ lb  by 4.

Then, you get the following result:

\frac{3}{8}\ lb\div4=(\frac{3}{8}\ lb) (\frac{1}{4})=\frac{3}{8*4}\ lb=\frac{3}{32} \ lb

As you can notice, this result matches with the Option D.

5 0
2 years ago
Hello I need a little here with this
Tomtit [17]
I may be wrong but I believe that <1=<2
5 0
2 years ago
Let f(x) = 2x2 − 2x + 7 and g(x) = x2 + 9x − 6. Find f(x) − g(x).
Nataly_w [17]

Answer:

Given information :

f(x) = 2x^2-2x+7\\g(x) = x^2+9x-6

Find f(x) - g(x)

f(x)-g(x) = (2x^2-2x+7) - (x^2+9x-6)

Distribute the negative to the second polynomial

f(x)-g(x)=2x^2-2x+7 -x^2 -9x + 6

optional : rearrange the terms

f(x)-g(x)=2x^2-x^2-2x-9x+7+6

Combine like terms and find f(x) - g(x)

f(x)-g(x) = x^2 - 11x + 13

5 0
3 years ago
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