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FinnZ [79.3K]
3 years ago
11

If m BAC = 90°, and m DAC = 689, then m BAD = [ ? ]°

Mathematics
1 answer:
Fudgin [204]3 years ago
7 0

Answer:

22 degrees

Step-by-step explanation:

90-68=22

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How do you get the value of 104 using the numbers 2,3,5, and 8 once
I am Lyosha [343]
(2x5+3)8=104

2x5=10
10+3=13
13x8=104

Hope that makes sense!  :)
7 0
3 years ago
Eric has attended summer camp for 5 weeks every summer for 6 years. How many days has he attended camp in 6 years?
quester [9]

Answer:

210 days

Step-by-step explanation:

There are 7 days in a week and since he goes for 5 weeks every summer, he goes for 35 days every year. Since he has attended for 6 years, multiply 35 by 6 to get 210, the number of days he has attended camp for.

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3 years ago
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Which table of values corresponds to the graph below?
Karolina [17]

The correct answer is the second answer choice.  It is the one that starts with (0,-2).

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3 years ago
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What is the slope of a line that is perpendicular to the lien whose equation is 2y=3x-1
bixtya [17]

<u>Answer:</u>

-2/3

<u>Step-by-step explanation:</u>

We are to find the slope of a line which is perpendicular of a line with an equation 2y=3x-1.

We know that the slope of line which is perpendicular to another line is the negative reciprocal of that perpendicular line.

So writing the given equation of a line in the slope intercept form:

2y=3x-1 ---> y=\frac{3}{2} x-\frac{1}{2}

Here the slope of this line is \frac{3}{2} so the slope of a line which is perpendicular to the given line will be -\frac{2}{3}.

3 0
3 years ago
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Simplify the rational expression. State any restrictions on the variable n^4-11n^2+30/ n^4-7n^2+10
djyliett [7]
To factor both numerator and denominator in this rational expression we are going to substitute n^{2} with x; so n^{2} =x and n ^{4} =  x^{2}. This way we can rewrite the expression as follows:
\frac{n^{4}-11n^{2} +30 }{n^{2}-7n^{2} +10 } =  \frac{ x^{2} -11x+30}{ x^{2} -7x+10}
Now we have two much easier to factor expressions of the form a x^{2} +bx+c. For the numerator we need to find two numbers whose product is c (30) and its sum b (-11); those numbers are -5 and -6. (-5)(-6)=30 and -5-6=-11.
Similarly, for the denominator those numbers are -2 and -5. (-2)(-5)=10 and -2-5=-7. Now we can factor both numerator and denominator:
\frac{ x^{2} -11x+30}{ x^{2} -7x+10} = \frac{(x-6)(x-5)}{(x-2)(x-5)}
Notice that we have (x-5) in both numerator and denominator, so we can cancel those out:
\frac{x-6}{x-2}
But remember than x= n^{2}, so lets replace that to get back to our original variable:
\frac{n^{2}-6 }{n^{2}-2 }
Last but not least, the denominator of rational expression can't be zero, so the only restriction in the variable is n^{2} -2 \neq 0
n^{2}  \neq 2
n \neq +or- \sqrt{2}
5 0
4 years ago
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