the second duckling is wandering by 2.6 units distance than the first duckling .
<u>Step-by-step explanation:</u>
Here we have , Two ducklings wander away from the nest while their mother is away. The first duckling's displacement (distance and direction) from the nest is (12,5) The second duckling's displacement is (13,-8) . We need to find How much farther did the second duckling wander than the first duckling. Let's find out:
Let a = (12,5) and b =(13,-8)
The distance each duckling wandered is the magnitude of its displacement vector. Therefore, the expression Distance second duck wandered is given by :
⇒ ![D = |b|-|a|](https://tex.z-dn.net/?f=D%20%20%3D%20%7Cb%7C-%7Ca%7C)
⇒ ![D = \sqrt{13^2+(-8)^2} -\sqrt{12^2+5^2}](https://tex.z-dn.net/?f=D%20%20%3D%20%5Csqrt%7B13%5E2%2B%28-8%29%5E2%7D%20-%5Csqrt%7B12%5E2%2B5%5E2%7D)
⇒ ![D = \sqrt{233} -\sqrt{169}](https://tex.z-dn.net/?f=D%20%20%3D%20%5Csqrt%7B233%7D%20-%5Csqrt%7B169%7D)
⇒ ![D =15.26 -13](https://tex.z-dn.net/?f=D%20%20%3D15.26%20-13)
⇒ ![D =2.6](https://tex.z-dn.net/?f=D%20%20%3D2.6)
Therefore , the second duckling is wandering by 2.6 units distance than the first duckling .
Answer:
No mode
Step-by-step explanation:
The mode is the statistical method in which the most repetitive number should be considered
Like if we take an example
1,1, 2, 2, 2, 4, 4,4,4
So here the mode is 4 as 4 is repeated 4 times
But in the given situation there is no mode as every number is written single time
Answer:
s = -7.8
Step-by-step explanation:
from the question 12=10(s+4)+50
<u>first step</u>
open the bracket and evaluate for the value of s
12=10(s+4)+50
12 = 10s + 40 + 50
12 = 10s + 90
collect or combine the like terms
12-90 = 10s
-78 = 10s
divide both side by 10
-78/10 = 10s/10
-7.8 = s
therefor s = -7.8
Answer:
Step-by-step explanation:
x²+24x+60=0
x²+24x+(24/2)²=-60+(24/2)²
(x+12)²=-60+144
(x+12)²=84