The empirical formula is No2 and molecular formula is N2O4
<h3>empirical formula calculation</h3>
find the moles of each reactant
=% composition/molar mass
molar mass of oxygen=16 g/mol ,while hat of nitrogen= 14 g/mol from periodic table
moles is therefore=
nitrogen= 30.43/14=2.174 moles
oxygen= 69.57/1 6=4.348 moles
find the mole ratio by dividing each moles with smallest number of mole( 2.174)
nitrogen = 2.174/2.174= 1
oxygen = 4.348/2.174=2
<h3>The balanced equation for its formation from the element nitrogen and oxygen is as below</h3><h3 /><h3>N2 +2 O2 → N2O4</h3>
therefore the empirical formula= NO2
molecular formula calculation
[NO2] n= 92.02 amu
[(14) + (16x2)]n = 92.02 amu
46n= 92.02
divide both side by 46
n=2
therefore the molecular formula is gotten by multiplying the empirical formula by 2= [NO2]2= N2O4