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marshall27 [118]
2 years ago
5

The net reaction of the calvin cycle is the conversion of co2 into the three-carbon sugar g3p. along the way, reactions rearrang

e carbon atoms among intermediate compounds and use the atp and nadph produced by the light reactions. in this exercise, you will track carbon atoms through the calvin cycle as required for the net production of one molecule of g3p. for each intermediate compound in the calvin cycle, identify the number of molecules of that intermediate and the total number of carbon atoms contained in those molecules. as an example, the output g3p is labeled for you: 1 molecule with a total of 3 carbon atoms. labels may be used once, more than once, or not at all. hints

Chemistry
1 answer:
pychu [463]2 years ago
3 0

a) 3 molecule of carbon dioxide (CO2) - 3 carbon atoms

b) 6 molecule of 3 - PGA - 18 carbon atoms ( 3 cabon atoms in 1   3 PGA molecule)

c)  6 molecule og G3P - 18 carbon atom ( 3 carbon atoms in G3P molecule )

d) 5 molecules of G3P - 15 carbon atom

e)  3 molecule of R5P   -   15 carbon atoms (  5 carbon atom of R5P  olecule )

f) 3 molecule of RuBP  -    15 carbon atoms ( r carbon atom of RuBp molecule )

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Consider the reaction of A(g) + B(g) + C(g) => D(g) for whichthe following data were obtained:
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Answer:

rate= k[A]²[B]²[C]

Explanation:

When concentration of A is increased two times ,keeping other's concentration constant , rate of reaction becomes 4 times .

So rate is proportional to [A]²

When concentration of B is increased two times , keeping other's concentration constant,rate of reaction becomes 4 times.

So rate is proportional to [B]²

When concentration of C is increased two times , keeping other's concentration constant, rate of reaction becomes 2 times.

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So rate= k[A]²[B]²[C]

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3 years ago
I HAVE ANSWER
Agata [3.3K]
<span>11.2G is the answer to this problem.
</span>
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When water freezes into ice, some of the properties have change. What stays the same.




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1L = 33.814 oz
xL = 2.75 oz

so it's a proportion

1L / 33.814 oz = xL / 2.75

solve for x

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the number in your problem, 2.75 oz, has 3 significant figures. so you can only round this number to 3 significant figures too.

your equipment isn't accurate enough to give a reading to 10 significant figures if that makes sense. you have to give the answer in terms of the term you use with the lowest significant figures.

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