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spin [16.1K]
3 years ago
9

How many moles of carbon are in 3.0 moles of C6H12O6?

Chemistry
1 answer:
rewona [7]3 years ago
3 0

Answer:

Hey there!:

1 mole of  C6H12O6 ------------------ 6 moles of C

3.0 moles of C6H12O6 ------------- ??

3.0 *6 / 1 =>

18.0 moles of C

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URGENTTTTT HELPPPP PLZZZ LAST TRYYY
algol13

Left Panel

A is an acid. Not the answer.

B is correct. That would be a base. But it is not an Arrhenius base. Keep reading.

C that is exactly what an Arrhenius base is.

D. No an acid of some sort would accept OH ions.

Right Panel

D is concentrated and it is also a weak base. Good cleaning fluid. Smells awful but it works.

8 0
3 years ago
1) What mass of Na2CO3 is required to make 50cc of its seminormal solution?
love history [14]

Answer:

m=1.325gNa_2CO_3

Explanation:

Hello,

In this case, by considering the given seminormal solution, we infer it is a 0.5-N solution which means that we can obtain the equivalent grams as shown below for the 55 cc (0.055 L) volume:

eq-g=0.5eq-g/L*0.050L=0.025eq-g

Next, since sodium carbonate has two sodium ions with a +1 oxidation state each, we can obtain the moles:

mol=0.025eq-gNa_2CO_3*\frac{1molNa_2CO_3}{2eq-gNa_2CO_3}\\ \\mol=0.0125molNa_2CO_3

Finally, the mass is computed by using its molar mass (106 g/mol)

m=0.0125molNa_2CO_3*\frac{106gNa_2CO_3}{1molNa_2CO_3} \\\\m=1.325gNa_2CO_3

Regards.

7 0
3 years ago
Write the overall reaction for cellular respiration
goblinko [34]
C6H12O6 + 6 O2 --> 6 CO2 + 6 H2O
7 0
3 years ago
Oxygen and hydrogen form the polyatomic hydroxide ion. What is its charge?
prohojiy [21]

Answer:

negative

the chage on hydroxide ions os negative

4 0
3 years ago
Read 2 more answers
A chef is cooking with a 2000-gram stainless steel skillet. Stainless steel has a specific heat capacity of 0.450 J/(g *oC). How
LuckyWell [14K]

Answer:

Q = 90,000 J

Explanation:

Given data:

Mass skillet = 2000 g

Specific heat capacity = 0.450 J/g.°C

Energy required to raise temperature = ?

Initial temperature = 25°C

Final temperature = 125°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 125°C - 25°C

ΔT = 100°C

Q = 2000 g × 0.450 J/g.°C × 100°C

Q = 90,000 J

8 0
3 years ago
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