Answer:
a)23.2 L
b)68.3kPa
c)7.5 atm
d)60.5L
e)1.67 atm
Explanation:
From Boyle's law:
P1V1=P2V2
P1= 748mmHg
P2=725mmHg
V1= 22.5L
V2??
V2= P1V1/P2= 748×22.5/725= 23.2 L
b)
V1=4.0L
P1= 205×10^3Pa
V2= 12.0L
P2=???
P2= P1V1/V2= 205×10^3×4/12
P2= 68.3×10^3 Pa or 68.3kPa
c)
P1= 1 atm
V1= 196.0L
P2= ??
V2= 26.0L
P2= P1V1/V2=1×196.0/26.0
P2= 7.5 atm
d)
V1= 40.0L
P1= 12.7×10^3Pa
V2=???
P2= 8.4×103Pa
V2= P1V1/P2= 12.7×10^3×40.0/8.4×103
V2=60.5L
e)
V1= 100mL
P1= 1atm
V2= 60mL
P2=???
P2= P1V1/V2= 1×100/60
P2= 1.67 atm
Answer:
The mass of potassium required to produce a known mass of potassium chloride
Explanation:
Stoichiometry deals with the relationship between amount of substances, mass of substances or volume of substances required in a chemical reaction. Stoichiometric relationships may involve reactants alone or reactants and products. These relationships are normally in the form of simple proportion.
A typical example is our answer option, the mass of potassium required could be used to determine the mass of potassium chloride produced after a balanced reaction equation is written.
Answer:
PN₂ = 191.3 Kpa
Explanation:
Given data:
Total pressure of tire = 245.0 Kpa
Partial pressure of PO₂ = 51.3 Kpa
Partial pressure of PCO₂ = 0.10 Kpa
Partial pressure of others = 2.3 Kpa
Partial pressure of PN₂ = ?
Solution:
According to Dalton law of partial pressure,
The total pressure inside container is equal to the sum of partial pressures of individual gases present in container.
Mathematical expression:
P(total) = P₁ + P₂ + P₃+ ............+Pₙ
Now we will solve this problem by using this law.
P(total) = PO₂ + PCO₂ + P(others)+ PN₂
245 Kpa = 51.3 Kpa + 0.10 Kpa + 2.3 Kpa + PN₂
245 Kpa = 53.7 Kpa+ PN₂
PN₂ = 245 Kpa - 53.7 Kpa
PN₂ = 191.3 Kpa
Molar mass is the mass of 1 mol of a compound
molar mass of a compound is the sum of the products of the molar masses of the individual elements by the number of atoms of the element
molar mass of Mn(ClO₃)₂ = molar mass of Mn + 2(molar mass of Cl + 3(molar mass of O))
Molar masses of the elements are
Mn - 55 g/mol
Cl - 35.5 g/mol
O - 16 g/mol
substituting the values
molar mass of Mn(ClO₃)₂ = 55 + 2 (35.5 + 3(16))
molar mass of Mn(ClO₃)₂ = 55 + 2 (35.5 + 48) = 55 + 2 (83.5) = 55 + 167 = 222
molar mass of Mn(ClO₃)₂ is 222 g/mol
