We need to know the relationship between atmospheric pressure and the density of gas particles in an area of increasing pressure.
The relationship is: As air pressure in an area increases, the density of the gas particles in that area increases.
For any gaseous substance, density of gas is directly proportional to pressure of gas.
This can be explained from idial gas edquation:
PV=nRT
PV=
RT [where, w= mass of substance, M=molar mass of substance]
PM=
RT
PM=dRT [where, d=density of thesubstance]
So, for a particular gaseous substance (whose molar mass is known), at particular temperature, pressure is directly related to density of gaseous substance.
Therefore, as air pressure in an area increases, the density of the gas particles in that area increases.
Answer:
0.0613 L
Explanation:
Given data
- Initial pressure (P₁): 1.00 atm
- Initial volume (V₁): 1.84 L
- Final pressure (P₂): 30.0 atm
Since we are dealing with an ideal gas, we can calculate the final volume using Boyle's law.
P₁ × V₁ = P₂ × V₂
V₂ = P₁ × V₁ / P₂
V₂ = 1.00 atm × 1.84 L / 30.0 atm
V₂ = 0.0613 L
Answer:
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Answer:
Ne 20: 10
and
Ne 22: 12
Explanation:
Ne-20:
N = A - Z = 20 - 10 = 10 neutrons
Ne-22:
N = A - Z = 22 - 10 = 12 neutrons
N: number of neutrons
A: mass number
Z: atomic number
Its Southern Hemisphere counterpart, marking the most southerly position at which the Sun can be directly overhead, is the Tropic of Capricorn. These tropics are two of the five major circles of latitude that mark maps of the Earth, besides the Arctic and Antarctic Circles and the Equator.