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Lelechka [254]
3 years ago
13

In the right triangle above, a = 99 and c= 124. Find the value of b, rounded to the nearest tenth.

Mathematics
1 answer:
Murljashka [212]3 years ago
8 0

Answer:

B= -40

Step-by-step explanation:

So a right triangle has to = 180

So we write the given, which 124+99

we are trying to get 180 so lets subtract that by the equation, 180-124+99

180-(124+99)

12+99=223

180-223

=-43

But in your case it has to be rounded to the nearest tenth

So the answer is -40

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Step-by-step explanation:

\int\frac{x^{4}}{x^{4} -1}dx

Adding and Subtracting 1 to the Numerator

\int\frac{x^{4} - 1 + 1}{x^{4} -1}dx

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We apply method of partial fractions to perform the integral

\frac{1}{(x-1)(x+1)(x^{2}+1)} = \frac{A}{x-1} + \frac{B}{x+1} + \frac{C}{x^{2} + 1}------------------------------------------(2)

\frac{1}{(x-1)(x+1)(x^{2}+1)} = \frac{A(x+1)(x^{2} +1) + B(x-1)(x^{2} +1) + C(x-1)(x+1)}{(x-1)(x+1)(x^{2} +1)}

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Answer:

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To solve this subject of the formulae given that A = πab.

<u>solution</u>

A = πab

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