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Andrew [12]
3 years ago
10

The amount a string stretches varies linearly with the mass applied to the spring, as can be seen in the video. In the video, wi

th no additional mass, the hanger was 30.6 cm off the ground. With 150 grams of additional mass, the hanger was 16.2 cm off the ground.
A wooden block stretched the spring so the hanger was 24.9 cm off the ground. Determine the mass of the wooden block, to at least 1 decimal place.
Mathematics
1 answer:
Gekata [30.6K]3 years ago
8 0

The answer for this question is 92.7 at leaat 1 decimal place


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The discriminant of the equation x^2 - 4x + 4 = 0 shows there will be solution(s).
Alex787 [66]

Answer:

one real

Answer: 1

Step-by-step explanation:

Givens

a = 1

b = -4

c = 4

Discriminate

Discriminate = sqrt(b^2 - 4*a*c)

Discriminate  = sqrt(  (-4)^2 - 4 * (1)(4) )

Discriminate = sqrt ( 16 - 16)

Discriminate = sqrt(0)

Discriminate = 0

That means the 1 real root is -  b / 2a = 4/(2*1) = - -2 = 2

3 0
2 years ago
se tiene que embaldosar el patio interior de un edificio con baldosas cuadradas de 30 cm de lado. El patio es rectangular y sus
shepuryov [24]

Answer:

40,000 baldosas

Step-by-step explanation:

Lo primero que debemos hacer aquí es calcular el área del patio rectangular.

El mejor enfoque para esto es convertir primero sus medidas a centímetros

Matemáticamente, 100 cm = 1 m, entonces 10 m se convierten en 1000 cm y 12 m se convierten en 1200 m.

El área de un rectángulo es L * B y, por lo tanto, tenemos 1200 * 1000 = 1,200,000 cm ^ 2

Ahora, para saber la cantidad de azulejos que tendrá el patio, necesitaremos dividir el área del patio por el área de los azulejos

Matemáticamente, eso sería 1,200,000 / 30 = 40,000 fichas

6 0
2 years ago
Find the intercept of the line -2x+5y=7
jeka57 [31]
Y intercept = 7/-2 or -3.5
5 0
3 years ago
6) 98=4b+ 2c; Find b if c=5
andreev551 [17]
The answer is b= 22 :)
8 0
3 years ago
hi I was just a little bit of time with my module and I didn't know what is answer of the module now please please be sure of th
GREYUIT [131]

1. 5 x 4 = A. 20

2.

\frac{2}{5}  \times 25 = 2 \times 5 = 10

the answer is D. 25

3.

\frac{3}{5}  \div 15 =  \frac{3}{5}  \times  \frac{1}{15}  =  \frac{1}{5}  \times  \frac{1}{5}  =  \frac{1}{25}

the answer is A. 1/25

4.

4 \div  \frac{1}{2}  = 4 \times  \frac{2}{1}  = 8

the answer is C. 8

5.

9 \div  \frac{1}{3}  = 9 \times  \frac{3}{1}  = 27

the answer is D. 27

6.

20 \div  \frac{1}{4}  = 20 \times  \frac{4}{1}  = 80

the answer is D. 80

7.

\frac{9}{10}  \div  \frac{1}{2}  =  \frac{9}{10}  \times  \frac{2}{1}  =  \frac{18}{10}  =  \frac{9}{5}  = 1 \frac{4}{5}

the answer is C. 1 4/5

8.

9 \div  \frac{3}{2}  = 9 \times  \frac{2}{3}  =  \frac{18}{ 3}  = 6

the answer is B. 6

9.

\frac{3}{4}  \div  \frac{3}{8}  =  \frac{3}{4}  \times  \frac{8}{3}  = 2

the answer is A. 2

3 0
2 years ago
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