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marshall27 [118]
3 years ago
8

A 12-foot piece of rope has 5 pieces that are each 1.25 feet cut from it. What is the rope's new length?

Mathematics
1 answer:
Alika [10]3 years ago
8 0

Answer:

5.75 feet

Step-by-step explanation:

5 x 1.25= 6.25

12-6.25=5.75

sorry if I got it wrong

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Identify the vertices of the feasible region for the given linear programming constraints.
vredina [299]

The vertices of the feasible region are as follows,

(-14, -11), (9, -11) and (6, 4)

What is a Feasible Region?

The area of the graph where all constraints are satisfied is the feasible solution zone or feasible region. It might also be thought of as the point where each constraint line's valid regions intersect. Any decision in this region would lead to a workable resolution for our objective function.

Vertices of the Feasible Region

As it can be seen in the graph, the vertices of the feasible region surrounded by the given constraints are:

(-14, -11), (9, -11) and (6, 4)

Learn more about feasible region here:

brainly.com/question/7243840

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7 0
2 years ago
Cari drew a line that was 9 inches long. She divided the line into 10 equal-length segments.
vivado [14]
Hello!

You divide how long the line is by the amount of segments

9 / 10 = 0.9

The answer is 0.9 inches long

Hope this helps!
8 0
3 years ago
Read 2 more answers
Need help please on this question
Gnesinka [82]

Answer:

a c

Step-by-step explanation:

5 0
3 years ago
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PLEASE WILL GIVE 50 POINTS PLEASE ANSWER ​
leva [86]

Answer:

AB = 75

BC = 60

AC = 45

m∠A = 53°

m∠B = 37°

m∠C = 90°

Step-by-step explanation:

<u>Trigonometric ratios</u>

\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Given:

\sf \tan(A)=\dfrac{60}{45}

Therefore:

  • side opposite angle A = BC = 60
  • side adjacent angle A = AC = 45

To find the length of AB (the hypotenuse), use Pythagoras’ Theorem:

a^2+b^2=c^2

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

⇒ AC² + BC² = AB²

⇒ 45² + 60² = AB²

⇒ AB² = 5625

⇒ AB = √5625

⇒ AB = 75

To find m∠A:

\implies\sf \tan(A)=\dfrac{60}{45}

\implies\sf A=\tan^{-1}\left(\dfrac{60}{45}\right)

\implies\sf A=53^{\circ}\:(nearest\:degree)

m∠C = 90° (as it is a right angle)

The interior angles of a triangle sum to 180°

⇒ m∠A + m∠B + m∠C = 180°

⇒ 53° + m∠B + 90° = 180°

⇒ m∠B = 180° - 53° - 90°

⇒ m∠B = 37°

4 0
2 years ago
Graph. Y + 1 = 1/3 ( x - 3)
zvonat [6]

Answer:

y=1/3x-2

Step-by-step explanation:

Plot a point at x=-2 and then for the slope (1/3, rise/run) count up 1 and over 3 starting from -2. This is a line. Y intercept at -2 and x intercept at 6.

6 0
3 years ago
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