Answer:
a) 151lb.
b) 6.25 lb
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean 
and standard deviation 
, a large sample size can be approximated to a normal distribution with mean and standard deviation 
.
In this problem, we have that:
So
a) The expected value of the sample mean of the weights is 151 lb.
(b) What is the standard deviation of the sampling distribution of the sample mean weight?
This is 
Answer:
Many options - 4/6 or 2/3 or 0.66
Step-by-step explanation:
When dividing fractions, we use KCF (keep, change, flip) so our new equation is 1/2 x 4/3. Just multiply! Your answer should be 4/6, and if it needs to be simplified, the answer is 2/3. The answer as a decimal is 0.66 !
Answer:
65950
Step-by-step explanation:
10,000 + 70 x 800 - 50
10,000 + 56,000 - 50
66,000 - 50
65950
Answer:
Rectangle
Step-by-step explanation:
(hope this helps!!)
