A function assigns the values. The range of the function will be between (-∞,10].
<h3>What is a Function?</h3>
A function assigns the value of each element of one set to the other specific element of another set.
The given function f(x)=10-x² is a parabolic function that is negative, therefore, will open downwards. Now, the range of the function can be found as,
f(x)=10-x²
y=10-x²
y-10 = -x²
-y+10 = x²
-y + 10 = 0
y = 10
Thus, the range of the function will be between (-∞,10].
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Answer:
Equivalent
Step-by-step explanation:
Look at 6/18. 18 divided by 6 is 3, which is the denominator. 6 divided by 6 is 1, so the numerator. So 1/3.
Find the Greatest Common Factor (GCF)
<u>GCF = 6y^6</u>
Factor out the GCF. (Write the GCF first. Then, in parenthesis divide each term by the GCF.)
6y^6(24y^8/6y^6 + 6y^6/6y^6)
Simplify each term in parenthesis
<u>6y^6(4y^2 + 1)</u>
Answer:
You add 2 and 3
Step-by-step explanation:
1.read the question it asks how to get 5 from 2,3,6,8
2.think.If you think about it 2 plus 3 equals 5
3.you have your answer
Answer:
a) Var[z] = 1600
D[z] = 40
b) Var[z] = 2304
D[z] = 48
c) Var[z] = 80
D[z] = 8.94
d) Var[z] = 80
D[z] = 8.94
e) Var[z] = 320
D[z] = 17.88
Step-by-step explanation:
In general
V([x+y] = V[x] + V[y] +2Cov[xy]
how in this problem Cov[XY] = 0, then
V[x+y] = V[x] + V[y]
Also we must use this properti of the variance
V[ax+b] = 
V[x]
and remember that
standard desviation = ![\sqrt{Var[x]}](https://tex.z-dn.net/?f=%5Csqrt%7BVar%5Bx%5D%7D)
a) z = 35-10x
Var[z] = 
Var[x] = 100*16 = 1600
D[z] = 
= 40
b) z = 12x -5
Var[z] = 
Var[x] = 144*16 = 2304
D[z] = 
= 48
c) z = x + y
Var[z] = Var[x+y] = Var[x] + Var[y] = 16 + 64 = 80
D[z] = 
= 8.94
d) z = x - y
Var[z] = Var[x-y] = Var[x] + Var[y] = 16 + 64 = 80
D[z] = = 8.94
e) z = -2x + 2y
Var[z] = 4Var[x] + 4Var[y] = 4*16 + 4*64 = 320
D[z] = 
= 17.88
