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ivolga24 [154]
3 years ago
7

0 1 2 3 20. (03.05 MC) What does > -4 indicate about the position of - - and - 4 on the number line? (1 point) 0 2/3 is locat

ed on the left of - 4 o 23 is located on the rightohy - 4 0 - 2 is located on the right of O and -4 is located on the left of 0 0 2/3 is located on the left of O and -4 is located on the right of O 21 (03.05 MC) Which inequal​

Mathematics
1 answer:
liq [111]3 years ago
3 0
You got this don’t give up
You might be interested in
What is the velocity of a car that traveled a total of 75 km north in 1.5 hours
Korvikt [17]

Answer:

13.89 m/s

Step-by-step explanation:

Velocity = displacement = time

75 km = 75000 m

1.5 hours = 5400 sec

applying the formula

velocity = 75000 m= 5400 s = 13.89 m/s

7 0
2 years ago
Read 2 more answers
CALCULUS - Find the values of in the interval (0,2pi) where the tangent line to the graph of y = sinxcosx is
Rufina [12.5K]

Answer:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

Step-by-step explanation:

We want to find the values between the interval (0, 2π) where the tangent line to the graph of y=sin(x)cos(x) is horizontal.

Since the tangent line is horizontal, this means that our derivative at those points are 0.

So, first, let's find the derivative of our function.

y=\sin(x)\cos(x)

Take the derivative of both sides with respect to x:

\frac{d}{dx}[y]=\frac{d}{dx}[\sin(x)\cos(x)]

We need to use the product rule:

(uv)'=u'v+uv'

So, differentiate:

y'=\frac{d}{dx}[\sin(x)]\cos(x)+\sin(x)\frac{d}{dx}[\cos(x)]

Evaluate:

y'=(\cos(x))(\cos(x))+\sin(x)(-\sin(x))

Simplify:

y'=\cos^2(x)-\sin^2(x)

Since our tangent line is horizontal, the slope is 0. So, substitute 0 for y':

0=\cos^2(x)-\sin^2(x)

Now, let's solve for x. First, we can use the difference of two squares to obtain:

0=(\cos(x)-\sin(x))(\cos(x)+\sin(x))

Zero Product Property:

0=\cos(x)-\sin(x)\text{ or } 0=\cos(x)+\sin(x)

Solve for each case.

Case 1:

0=\cos(x)-\sin(x)

Add sin(x) to both sides:

\cos(x)=\sin(x)

To solve this, we can use the unit circle.

Recall at what points cosine equals sine.

This only happens twice: at π/4 (45°) and at 5π/4 (225°).

At both of these points, both cosine and sine equals √2/2 and -√2/2.

And between the intervals 0 and 2π, these are the only two times that happens.

Case II:

We have:

0=\cos(x)+\sin(x)

Subtract sine from both sides:

\cos(x)=-\sin(x)

Again, we can use the unit circle. Recall when cosine is the opposite of sine.

Like the previous one, this also happens at the 45°. However, this times, it happens at 3π/4 and 7π/4.

At 3π/4, cosine is -√2/2, and sine is √2/2. If we divide by a negative, we will see that cos(x)=-sin(x).

At 7π/4, cosine is √2/2, and sine is -√2/2, thus making our equation true.

Therefore, our solution set is:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

And we're done!

Edit: Small Mistake :)

5 0
2 years ago
I reallly need help quick with this
Rasek [7]

you can do that on here


8 0
3 years ago
Read 2 more answers
If one person runs 8.1 miles per hour in one direction and another with a speed of 6.3 in an other direction how many hours woul
djverab [1.8K]

Answer:

1.4 hours

Step-by-step explanation:

Runner A:

Speed = 8.1 mph

Time, = t

Runner B :

Speed = 6.3 mph

Time, = t

Distance apart = 20.16 miles

Distance = speed * time

Distance of Runner A + Distance of runner B = distance apart

8.1t + 6.3t = 20.16

14.4t = 20.16

t = 20.16 / 14.4

t = 1.4 hours

Number of hours, t = 1.4 hours

7 0
2 years ago
I’m looking for number 3 on the picture attached
Nataliya [291]
25 is the answer for number 3
8 0
2 years ago
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