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yawa3891 [41]
3 years ago
10

Find the surface area of a rectangular prism with a height of 6 inches, a width of 7 inches, and a length of 13 inches.

Mathematics
1 answer:
madam [21]3 years ago
5 0
The answer is B)422 ,you're welcome :)
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Can't figure it out!!
Zanzabum
\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
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f(x)= \cfrac{1}{x}  \qquad 
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\cfrac{\frac{1}{b}-\frac{1}{2}}{b-2}=-\cfrac{1}{10}\implies 
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\bf \cfrac{2-b}{2b}=\cfrac{2-b}{10}\implies 20-10b=4b-2b^2\impliedby cross-multiplying
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8 0
3 years ago
hannahs exercise goal is to walk at least 6 1/2 miles this week. she has already walked 2 3/4 miles this week. write and solve a
Ne4ueva [31]

We want to write an inequality that tells how much Hannah should walk this week. The inequality will be:

x ≥ (3 + 3/4) mi

<h3>Finding the inequality:</h3>

We know that she already did walk 2 3/4 miles this week, and she wants to walk at least 6 1/2 miles.

So to reach that minimum, she needs to walk:

(6  1/2)mi - (2 + 3/4) mi = (3 + 3/4) mi

And she can walk that or more, so the inequality is:

x ≥ (3 + 3/4) mi

Where x represents how much she will walk this week.

If you want to learn more about inequalities, you can read:

brainly.com/question/11234618

6 0
2 years ago
Graph the solution of the inequality -3 &lt; 2x – 7 &lt; 5 on the number line.
Gelneren [198K]

Answer:2<x<6

Step-by-step explanation:

Solve for x

7 0
2 years ago
Two machines are used for filling plastic bottles to a net volume of 16.0 ounces. A member of the quality engineering staff susp
aleksandrvk [35]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if the two machines are filling the bottles with a net volume of 16.0 ounces or if at least one of them is different.

The parameter of interest is μ₁ - μ₂, if both machines are filling the same net volume this difference will be zero, if not it will be different.

You have one sample of ten bottles filled by each machine and the net volume of the bottles are measured, determining two variables of interest:

Sample 1 - Machine 1

X₁: Net volume of a plastic bottle filled by the machine 1.

n₁= 10

X[bar]₁= 16.02

S₁= 0.03

Sample 2 - Machine 2

X₂: Net volume of a plastic bottle filled by the machine 2

n₂= 10

X[bar]₂= 16.01

S₂= 0.03

With p-values 0.4209 (for X₁) and 0.6174 (for X₂) for the normality test and using α: 0.05, we can say that both variables of interest have a normal distribution:

X₁~N(μ₁;δ₁²)

X₂~N(μ₂;δ₂²)

Both population variances are unknown you have to conduct a homogeneity of variances test to see if they are equal (if they are you can conduct a pooled t-test) or different (if the variances are different you have to use the Welche's t-test)

H₀: δ₁²/δ₂²=1

H₁: δ₁²/δ₂²≠1

α: 0.05

F= \frac{S^2_1}{S^2_2} * \frac{Sigma^2_1}{Sigma^2_2} ~~F_{n_1-1;n_2-1}

Using a statistic software I've calculated the test

F_{H_0}= 1.41

p-value 0.6168

The p-value is greater than the significance level, so the decision is to not reject the null hypothesis then you can conclude that both population variances for the net volume filled in the plastic bottles by machines 1 and 2 are equal.

To study the difference between the population means you can use

t= \frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }  ~~t_{n_1+n_2-2}

The hypotheses of interest are:

H₀: μ₁ - μ₂ = 0

H₁: μ₁ - μ₂ ≠ 0

α: 0.05

Sa= \sqrt{\frac{(n_1-1)S^2_1+(N_2-1)S^2_2}{n_1+n_2-2}} = \sqrt{\frac{9*9.2*10^{-4}+9*6.5*10^{-4}}{10+10-2} } = 0.028= 0.03

t_{H_0}= \frac{(16.02-16.01)-0}{0.03*\sqrt{\frac{1}{10} +\frac{1}{10} } } = 0.149= 0.15

The p-value for this test is: 0.882433

The p-value is greater than the significance level, the decision is to not reject the null hypothesis.

Using a significance level of 5%, there is no significant evidence to reject the null hypothesis. You can conclude that the population average of the net volume of the plastic bottles filled by machine one and by machine 2 are equal.

I hope this helps!

8 0
3 years ago
(2x -3) + (4c + 20) i need help
Stella [2.4K]

Answer:

=2x+4c+17

Step-by-step explanation:

(2x-3)+(4c+20)

=2x-3+4c+20

=2x+4c-3+20

=2x+4c+17

4 0
3 years ago
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