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professor190 [17]
3 years ago
13

Which is the real world situation that can be described by a linear inequality

Mathematics
1 answer:
garik1379 [7]3 years ago
7 0

Answer:

Pretty sure it's B

Step-by-step explanation:

Everything else would be more like an equation. I think B is the only inequality.

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How can yo do 9087 divided by 12
vodka [1.7K]
Answer

9087 divide by 12
=752.25
3 0
3 years ago
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If QT is 9 and TP is 8 Find the length of the following:<br><br>RP<br>RT<br>RS​
anyanavicka [17]

Answer:

i. RP = 17

ii. RT = 15

iii. RS = 30

Step-by-step explanation:

Given that; QT = 9 and TP = 8.

From the diagram, join R to P. Thus RP = QP (radius of the circle)

                        RP = QT + TP

                             = 9 + 8

                         RP = 17

Applying Pythagoras theorem to triangle TRP;

             RT = \sqrt{(RP)^{2} - (TP)^{2} }

                  = \sqrt{17^{2} - 8^{2} }

                 = \sqrt{225}

                 = 15

∴           RT = 15

But, RT = TS = 15.

So that;

       RS = 15 + 15

             = 30

        RS = 30

Therefore;  RP = 17, RT = 15 and RS = 30.

6 0
3 years ago
Which expression is equivalent to 3(-5x + 2) + 20x - 7
lukranit [14]

about Answer: The correct answer would be <u><em>d) 5x - 1</em></u>

Step-by-step explanation:

Simplify or Evaluate the expression and Combine like terms

3(-5x + 2) + 20x - 7

Learn more about how to solve the problem here: brainly.com/question/17829483

7 0
3 years ago
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suppose you know that two angles,angle A and B,are supplementary.The measure of angle A is 5 times the measure of angle B. Find
Morgarella [4.7K]
Angle A is 150
Angle B is 30 
Supplementary= 180, so....
Angle A + Angle B = 180
150 + 30= 180

hope this helps
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3 years ago
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Hello I need help Finding the probability
Stolb23 [73]
Each petal of the region R is the intersection of two circles, both of diameter 10. Each petal in turn is twice the area of a circular segment bounded by a chord of length 5\sqrt2, which implies the segment is subtended by an angle of \dfrac\pi2. This means the area of the segment is

\text{area}_{\text{segment}}=\text{area}_{\text{sector}}-\text{area}_{\text{triangle}}
\text{area}_{\text{segment}}=\dfrac{25\pi}4-\dfrac{25}2

This means the area of one petal is \dfrac{25\pi}2-25, and the area of R is four times this, or 50\pi-100.

Meanwhile, the area of G is simply the area of the square minus the area of R, or 10^2-(50\pi-100)=200-50\pi.

So

\mathbb P(X=R)=\dfrac{50\pi-100}{100}=\dfrac\pi2-1
\mathbb P(X=G)=\dfrac{200-50\pi}{100}=2-\dfrac\pi2
\mathbb P((X=R)\land(X=G))=0 (provided these regions are indeed disjoint; it's hard to tell from the picture)
\mathbb P((X=R)\lor(X=G))=\mathbb P(X=R)+\mathbb P(X=G)=1

4 0
4 years ago
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