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Goshia [24]
3 years ago
15

In the figure, what is the value of z? a. 2.9 b. 5.6 c. 6 d 8.75

Mathematics
1 answer:
nirvana33 [79]3 years ago
5 0

i believe that the answer is D 8.75

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What is the radian equivalent for 180°? 2 pi radians pi radians startfraction pi over 2 endfraction radians
alukav5142 [94]

Answer:

180° = pi radians

Step-by-step explanation:

360° = 2pi radians

90° = pi/2 radians

see image

180° is pi radians.

8 0
3 years ago
The graph below shows a company's profit f(x), in dollars, depending on the price of pens x, in dollars, sold by the company:
Volgvan

The answers to the various part as well as its reasons are given below

<h3 /><h3>Part A:</h3>
  • The x-intercepts shows a zero profit.
  • The maximum value of the graph tells  or depict the maximum profit.
  • The function is one that goes up or increases upward until it reach the vertex and then it falls or decreases after it.
  • This implies that the profit goes up as it reaches the peak at the vertex and it goes down after the vertex up until it gets to zero.
  • The  profits are negative as seen on the left of the first zero and on the right of the second zero.

<h3>Part B:</h3>

An approximate average rate of change of the graph from x = 3 to x = 5, shows the reduction in profit from  3 to 5.

<h3>Part C:</h3>

Based on the above,  the domain is one that is held back or constrained by x = 0 .

We are compelled at x = 6 due to the fact that we have to maneuver a negative profit.

Learn more about quadratic function from

brainly.com/question/25841119

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4 0
2 years ago
23. Which point has a horizontal distance of 4 units and a vertical distance of 5 units from (6, - 4)?
vagabundo [1.1K]

Answer:

(2,1)

Step-by-step explanation:

7 0
3 years ago
Which is bigger 16.45 or 16.454
patriot [66]
16.454 is .004 greater than 16.45(0), hope this helps!
7 0
3 years ago
X2 + 5x – 4 = 3x - 1
Zanzabum

Answer:

<h2>x = -3 or x = 1</h2>

Step-by-step explanation:

x^2+5x-4=3x-1\qquad\text{subtract}\ 3x\ \text{from both sides}\\\\x^2+5x-3x-4=3x-3x-1\\\\x^2+2x-4=-1\qquad\text{add 1 to both sides}\\\\x^2+2x-4+1=-1+1\\\\x^2+2x-3=0\\\\x^2+3x-x-3=0\\\\x(x+3)-1(x+3)=0\\\\(x+3)(x-1)=0\iff x+3=0\ \vee\ x-1=0\\\\x+3=0\qquad\text{subtract 3 from both sides}\\x+3-3=0-3\\\boxed{x=-3}\\\\x-1=0\qquad\text{add 1 to both sides}\\x-1+1=0+1\\\boxed{x=1}

8 0
3 years ago
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