End behavior of function

Mathematics

1 answer:

artcher [175]3 years ago

5 0

Answer:

both questions answer is 22 this is your answer friend

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Which solution is possible: 7+x <19 x=4 x=12 x=13 x=19 Other:

Tamiku [17]

Answer:

x = 4

Step-by-step explanation:

Note that it is only less than, not less than or equal too. Numbers that are 11 & less are the only ones that work.

x = 4 is your only answer choice that is less than 11, therefore is your only answer.

4 0

3 years ago

Read 2 more answers

What is the peremeter of this polygon? (With picture)

lyudmila [28]

Check the picture below.

so.. simply, use the distance formula, to get their length an add them up, and that's the perimeter of the polygon.

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ -1}}\quad ,&{{ 2}})\quad 
% (c,d)
&({{ 2}}\quad ,&{{ 4}})\\
&({{ 2}}\quad ,&{{ 4}})\quad 
% (c,d)
&({{ 3}}\quad ,&{{ -2}})\\
&({{ 3}}\quad ,&{{ -2}})\quad 
% (c,d)
&({{ -2}}\quad ,&{{ -3}})\\
&({{ -2}}\quad ,&{{ -3}})\quad 
% (c,d)
&({{ -1}}\quad ,&{{ 2}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}$

$\bf -------------------------------\\\\
d=\sqrt{[2-(-1)]^2+(4-2)^2}\implies d=\sqrt{(2+1)^2+(2)^2}
\\\\\\
d=\sqrt{3^2+2^2}\implies \boxed{d=\sqrt{13}}\\\\
-------------------------------\\\\
d=\sqrt{(3-2)^2+(-2-4)^2}\implies d=\sqrt{1^2+(-6)^2}\implies \boxed{d=\sqrt{37}}\\\\
-------------------------------\\\\
d=\sqrt{(-2-3)^2+[-3-(-2)]^2}\implies d=\sqrt{(-5)^2+(-3+2)^2}
\\\\\\
d=\sqrt{(-5)^2+(-1)^2}\implies \boxed{d=\sqrt{26}}$

$\\\\
-------------------------------\\\\
d=\sqrt{[-1-(-2)]^2+[2-(-3)]^2}\implies d=\sqrt{(-1+2)^2+(2+3)^2}
\\\\\\
d=\sqrt{(1)^2+(5)^2}\implies \boxed{d=\sqrt{26}}$

so, those are their lengths, sum them all up, that's the polygon's perimeter.