Question

What is the perimeter of the quadrilateral formed by joining the points P(-5, 1), Q(3, 7), R(6, 3), and S(-2, -3)?

Answer 1

Answer:

The answer to your question is the letter A. 30 units

Step-by-step explanation:

Data

P (-5, 1)

Q (3, 7)

R (6, 3)

S (-2, -3)

Process

1.- Find the distance from P-Q, Q-R, R-S, and P-S

dPQ = $\sqrt{(3 + 5)^{2}+ (7 - 1)^{2}}$

dPQ = $\sqrt{8^{2} + 6^{2}}$

dPQ = $\sqrt{64 + 36}$

dPQ = $\sqrt{100}$

dPQ = 10 units

dQR = $\sqrt{(6 - 3)^{2} + (3 - 7)^{2}}$

dQR = $\sqrt{3^{2} + 4^{2}}$

dQR = $\sqrt{9 + 16}$

dQR = $\sqrt{25}$

dQR = 5 units

dRS = $\sqrt{(-2- 6)^{2}+ (-3 - 3)^{2}}$

dRS = $\sqrt{-8^{2} - 6^{2}}$

dRS = $\sqrt{64 + 36}$

dRS = $\sqrt{100}$

dRS = 10 units

dPS = $\sqrt{(-2+ 5)^{2}+ (-3 - 1)^{2}}$

dPS = $\sqrt{3^{2} - 4^{2}}$

dPS = $\sqrt{9 + 16}$

dPS = $\sqrt{25}$

dPS = 5 units

2.- Calculate the Perimeter

Perimeter = 10 + 5 + 10 + 5

               = 30 units