Answer:
![Wavelength=232.56\ m](https://tex.z-dn.net/?f=Wavelength%3D232.56%5C%20m)
Explanation:
The relation between frequency and wavelength is shown below as:
![c=frequency\times Wavelength](https://tex.z-dn.net/?f=c%3Dfrequency%5Ctimes%20Wavelength)
c is the speed of light having value ![3\times 10^8\ m/s](https://tex.z-dn.net/?f=3%5Ctimes%2010%5E8%5C%20m%2Fs)
Given, Frequency = 1290 kHz =
(As 1 kHz = 1000 Hz )
Thus, Wavelength is:
![Wavelength=\frac{c}{Frequency}](https://tex.z-dn.net/?f=Wavelength%3D%5Cfrac%7Bc%7D%7BFrequency%7D)
![Wavelength=\frac{3\times 10^8}{1290\times 10^{3}}\ m](https://tex.z-dn.net/?f=Wavelength%3D%5Cfrac%7B3%5Ctimes%2010%5E8%7D%7B1290%5Ctimes%2010%5E%7B3%7D%7D%5C%20m)
![Wavelength=232.56\ m](https://tex.z-dn.net/?f=Wavelength%3D232.56%5C%20m)
For the net charge to be +3,the mystery charge should be is -2 and net force is towards left.
- In first problem, overall charge should be -2 (as mentioned in question).
- So charge labelled with ? should be negative charge ( -ve).
- There will be net force on -1 charge towards +3 charge (left). For box (b)net force towards right
- For box c) net force towards right.
- It is often referred to as electric charge, electrical charge, or electrostatic charge, and denoted by the letter q, is a property of a unit of matter that indicates how many more or less electrons than protons it has.
- When retained in an electric or magnetic field, matter's basic physical feature known as electric charge causes it to experience a force.
To learn more about charge visit:
brainly.com/question/14713274
#SPJ9
Answer:
![\large \boxed{\text{1.11 kg}}](https://tex.z-dn.net/?f=%5Clarge%20%5Cboxed%7B%5Ctext%7B1.11%20kg%7D%7D)
Explanation:
The buoyant force in kilograms is given by
![F = V(\rho_{\text{air}} - \rho_{\text{He}})](https://tex.z-dn.net/?f=F%20%3D%20V%28%5Crho_%7B%5Ctext%7Bair%7D%7D%20-%20%5Crho_%7B%5Ctext%7BHe%7D%7D%29)
![\begin{array}{rcl}F& = & \text{1 m}^{3} \times(\text{1.29 kg/m}^{3} - \text{0.18 kg/m}^{3})\\ & = & \textbf{1.11 kg}\\\end{array}\\\text{A cubic metre of helium can float a mass of $\large \boxed{\textbf{1.11 kg}}$}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7DF%26%20%3D%20%26%20%5Ctext%7B1%20m%7D%5E%7B3%7D%20%5Ctimes%28%5Ctext%7B1.29%20kg%2Fm%7D%5E%7B3%7D%20-%20%5Ctext%7B0.18%20kg%2Fm%7D%5E%7B3%7D%29%5C%5C%20%26%20%3D%20%26%20%5Ctextbf%7B1.11%20kg%7D%5C%5C%5Cend%7Barray%7D%5C%5C%5Ctext%7BA%20cubic%20metre%20of%20helium%20can%20float%20a%20mass%20of%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B1.11%20kg%7D%7D%24%7D)
Answer:
10.88 g
Explanation:
We have:
[CH₃COOH] = 0.10 M
pH = 5.25
Ka = 1.80x10⁻⁵
V = 250.0 mL = 0.250 L
The pH of the buffer solution is:
(1)
By solving equation (1) for [CH₃COONa*3H₂O] we have:
![[CH_{3}COONa*3H_{2}O] = 10^{-0.495} = 0.32 M](https://tex.z-dn.net/?f=%5BCH_%7B3%7DCOONa%2A3H_%7B2%7DO%5D%20%3D%2010%5E%7B-0.495%7D%20%3D%200.32%20M)
Hence, the mass of the sodium acetate tri-hydrate is:
![m = moles*M = [CH_{3}COONa*3H_{2}O]*V*M = 0.32 mol/L*0.250 L*136 g/mol = 10.88 g](https://tex.z-dn.net/?f=m%20%3D%20moles%2AM%20%3D%20%5BCH_%7B3%7DCOONa%2A3H_%7B2%7DO%5D%2AV%2AM%20%3D%200.32%20mol%2FL%2A0.250%20L%2A136%20g%2Fmol%20%3D%2010.88%20g)
Therefore, the number of grams of CH₃COONa*3H₂O needed to make an acetic acid/sodium acetate tri-hydrate buffer solution is 10.88 g.
I hope it helps you!
The final gas pressure : 175.53 atm
<h3>Further explanation</h3>
Maybe the complete question is like this :
A ridged steel tank filled with 62.7 l of nitrogen gas at 85.0 atm and 19 °C is heated to 330 °C while the volume remains constant. what is the final gas pressure?
The volume remains constant⇒Gay Lussac's Law
<em>When the volume is not changed, the gas pressure in the tube is proportional to its absolute temperature </em>
![\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7BP_1%7D%7BT_1%7D%3D%5Cdfrac%7BP_2%7D%7BT_2%7D)
P₁=85 atm
T₁=19+273=292 K
T₂=330+273=603 K
![\tt P_2=\dfrac{P_1\times T_2}{T_1}\\\\P_2=\dfrac{85\times 603}{292}\\\\P_2=175.53~atm](https://tex.z-dn.net/?f=%5Ctt%20P_2%3D%5Cdfrac%7BP_1%5Ctimes%20T_2%7D%7BT_1%7D%5C%5C%5C%5CP_2%3D%5Cdfrac%7B85%5Ctimes%20603%7D%7B292%7D%5C%5C%5C%5CP_2%3D175.53~atm)