NH3(aq) + HCl(aq) ⇒ NH4Cl(aq) >>> (1)
∵ C = n/V; C= concentration, n= No. of moles, and V= volume (L)
∴ n = C*V, n(HCl) = 0.050*(50/1000) = 0.0025 moles
n(NH3) = 0.050*(50/1000) = 0.0025 moles
So, the limiting no. of moles is 0.0025 moles >>> (2)
∵ NH3 is weak base, and HCl is strong Acid (and have the same number of moles) >>> So, without any calculation we can notice that the formed salt (NH4Cl) is acidic salt and the pH is less than 7.
From (1) and (2), The no. of moles of NH4Cl is 0.0025 moles >>> (3)
∴ the concentration of [NH4Cl] = 0.0025 / (total volume per L)
= 0.0025 / ((50 + 50) / 1000) = 0.025 M
NH4+(aq) ⇔ NH3(aq) + H+(aq) >>> (4)
(0.025 - x) (x) (x) >>> (5)
∵ Ka = [NH3] [H+] / [NH4+] >>>> (6)
Ka = Kw / Kb, Kb = 1.8 * 10^-5 >>> (7)
∴ Ka = 10^-14 / 1.8*10^-5 = 5.56*10^-10 >>> (8)
From (4), (5), (7) and (8)
Ka = 5.56*10^-10 = (x * x) / (0.025-x) , we will assume that (0.025 - x) = 0.025
∴ x^2 = (5.56*10^-10)(0.025) = 139*10^-13
∴ x = 3.73*10^-6 = [H+]
∵ pH = - log [H+]
∴ pH = - log 3.73*10^-6 = 5.43
Answer:
Sodium sulfite (Na2SO3)
Explanation:
Sulfuric acid is able to displace volatile acids from their corresponding salts and the acids displaced are unstable and they break down to give volatile products
For example, in to reaction of sulfuric acid and sodium sulfite; two processes occur
1. Sulfuric acid forms sodium sulfate and sulfurous acid
Na2SO3(s) + H2SO4(aq) -------> Na2SO4(aq) + H2SO3
2. The H2SO3 is unstable thereby decompose spontaneously to water and sulfur dioxide gas.
H2SO3 -----------> H2O(l) + SO2(g)
Final reaction gives;
Na2SO3(s) + H2SO4 (aq) ---------> Na2SO4(aq) + H2O(l) + SO2(g)
Answer:
Tapeworm, also called cestode, any member of the invertebrate class Cestoda (phylum Platyhelminthes), a group of parasitic flatworms containing about 5,000 species. ... Tapeworms also lack a circulatory system and an organ specialized for gas exchange.
The mass of Li2O : 104.58 grams
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Further explanation
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Given
3.5 moles of Li2O
Required
The mass
Solution
The mole is the number of particles contained in a substance
1 mol = 6.02.10²³
Moles can also be determined from the amount of substance mass and its molar mass
mol(n) = mass(m) : MW(molecular weight)
Input the value :
mass = mol x MW Li2O
mass = 3.5 mol x 29,88 g/mol
mass = 104.58 g grams
mass = 2.957 g
Answer:
The right answer is "6 gm".
Explanation:
Given:
Amount of Li,
= 0.3 gm
Battery rated,
= 5 Ah per cell
Total number of cells,
= 4
The total power limit will be:
=
=
hence,
The amount of Li in battery will be:
=
=
(Allowed for transportation).